24 divided by 2 and 2/3
1 answer:
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<span>(3,5),
(5,8),
(6,13)
------
(14,26)/3
then use the point slope form of a line to find equation of line
</span>
<span>
Find y-intercept for x = 0.
</span>
<span>
</span>
(5,8),
(6,13)
------
(14,26)/3
then use the point slope form of a line to find equation of line
</span>
<span>
Find y-intercept for x = 0.
</span>
</span>
-17 + n/5 = 33
First, we can start out by regrouping our terms. This will switch our fraction and number around and also make the original addition to subtraction.
Second, we can start out our goal by trying to get the variable (n) on one side by itself and to equal something. Let's begin by adding 17 to each side of the problem.
Third, we can now add the numbers on the right side of our problem. Simple. Add 33 + 17 to get 50.
Fourth, we now have to multiply both sides by 5. Why? We are getting rid of the fraction so that the variable can become by itself.
Fifth, our last step is to multiply 50 × 5. Use a calculator, long multiplication, etc. 50 × 5 = 250.
Answer:
First, we can start out by regrouping our terms. This will switch our fraction and number around and also make the original addition to subtraction.
Second, we can start out our goal by trying to get the variable (n) on one side by itself and to equal something. Let's begin by adding 17 to each side of the problem.
Third, we can now add the numbers on the right side of our problem. Simple. Add 33 + 17 to get 50.
Fourth, we now have to multiply both sides by 5. Why? We are getting rid of the fraction so that the variable can become by itself.
Fifth, our last step is to multiply 50 × 5. Use a calculator, long multiplication, etc. 50 × 5 = 250.
Answer:
Answer:
Following are the solution to this question:
Step-by-step explanation:
They provide various boxes or various objects. It also wants objects to be distributed into containers, so no container is empty. All we select k objects of r to keep no boxes empty, which (r C k) could be done. All such k artifacts can be placed in k containers, each of them in k! Forms. There will be remaining objects. All can be put in any of k boxes. Therefore, these
objects could in the
manner are organized. Consequently, both possible ways to do this are
Consequently, the number of ways that r objects in k different boxes can be arranged to make no book empty is every possible one