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guapka [62]
2 years ago
9

What is the probability of picking a blue marble and rolling an odd number?

Mathematics
1 answer:
Paladinen [302]2 years ago
6 0

Answer:

3/6 chance.

Step-by-step explanation:

To roll an odd number on a six sided dice (Guessing it's six sided) you would have to roll either a 1, 3, or 5.  That would it 3 choices.  You get the six by taking the amount (like the amount of sides on the dice).  You would then have a 3/6 chance of rolling an odd number.

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Write 5 1/3% as a fraction in simplest form
goblinko [34]
5+1/3=                                                                                                              15/3+1/3=                                                                                                        16/3
7 0
3 years ago
Read 2 more answers
. Which of the following statements is not true?
lesantik [10]

Answer:

If x^2 = 1, then x = 1 is NOT true because x can also be -1.

6 0
2 years ago
Need help on both of them
Vlad1618 [11]
7) Write the decimal number as a fraction
(over 1)
2.18 = 2.18 / 1

Multiplying by 1 to eliminate 3 decimal places
we multiply top and bottom by 3 10's

Numerator (N)
N = 2.18 × 10 × 10 × 10 = 2180
Denominator (D)
D = 1 × 10 × 10 × 10 = 1000

N / D = 2180 / 1000

Simplifying our fraction

= 2180/1000

= 109/50

= 2  9/50

8)7 ^{-5}  =  \frac{1}{7^{5}}
6 0
3 years ago
Answer the question below please
DaniilM [7]

The correct answer is : of those planning to not to go on vacation, more of them are women.

The correct answer is (C)

<h3>What is probability?</h3>

Probability means possibility. It is a branch of mathematics that deals with the occurrence of a random event

Given:  total people asked =145

The first option is not correct because plan to go on vacation women are more than men.

The second option is also incorrect because more women were asked than men.

The third option is correct because out of planning who were not going any vacation, women are more than of men.

The fourth option is incorrect because More men plan to go on vacation.

Learn more about probability here:

brainly.com/question/11234923

#SPJ1

5 0
2 years ago
I am having trouble with this relative minimum of this equation.<br>​
Norma-Jean [14]

Answer:

So the approximate relative minimum is (0.4,-58.5).

Step-by-step explanation:

Ok this is a calculus approach.  You have to let me know if you want this done another way.

Here are some rules I'm going to use:

(f+g)'=f'+g'       (Sum rule)

(cf)'=c(f)'          (Constant multiple rule)

(x^n)'=nx^{n-1} (Power rule)

(c)'=0               (Constant rule)

(x)'=1                (Slope of y=x is 1)

y=4x^3+13x^2-12x-56

y'=(4x^3+13x^2-12x-56)'

y'=(4x^3)'+(13x^2)'-(12x)'-(56)'

y'=4(x^3)'+13(x^2)'-12(x)'-0

y'=4(3x^2)+13(2x^1)-12(1)

y'=12x^2+26x-12

Now we set y' equal to 0 and solve for the critical numbers.

12x^2+26x-12=0

Divide both sides by 2:

6x^2+13x-6=0

Compaer 6x^2+13x-6=0 to ax^2+bx+c=0 to determine the values for a=6,b=13,c=-6.

a=6

b=13

c=-6

We are going to use the quadratic formula to solve for our critical numbers, x.

x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}

x=\frac{-13 \pm \sqrt{13^2-4(6)(-6)}}{2(6)}

x=\frac{-13 \pm \sqrt{169+144}}{12}

x=\frac{-13 \pm \sqrt{313}}{12}

Let's separate the choices:

x=\frac{-13+\sqrt{313}}{12} \text{ or } \frac{-13-\sqrt{313}}{12}

Let's approximate both of these:

x=0.3909838 \text{ or } -2.5576505.

This is a cubic function with leading coefficient 4 and 4 is positive so we know the left and right behavior of the function. The left hand side goes to negative infinity while the right hand side goes to positive infinity. So the maximum is going to occur at the earlier x while the minimum will occur at the later x.

The relative maximum is at approximately -2.5576505.

So the relative minimum is at approximate 0.3909838.

We could also verify this with more calculus of course.

Let's find the second derivative.

f(x)=4x^3+13x^2-12x-56

f'(x)=12x^2+26x-12

f''(x)=24x+26

So if f''(a) is positive then we have a minimum at x=a.

If f''(a) is negative then we have a maximum at x=a.

Rounding to nearest tenths here:  x=-2.6 and x=.4

Let's see what f'' gives us at both of these x's.

24(-2.6)+25

-37.5  

So we have a maximum at x=-2.6.

24(.4)+25

9.6+25

34.6

So we have a minimum at x=.4.

Now let's find the corresponding y-value for our relative minimum point since that would complete your question.

We are going to use the equation that relates x and y.

I'm going to use 0.3909838 instead of .4 just so we can be closer to the correct y value.

y=4(0.3909838)^3+13(0.3909838)^2-12(0.3909838)-56

I'm shoving this into a calculator:

y=-58.4654411

So the approximate relative minimum is (0.4,-58.5).

If you graph y=4x^3+13x^2-12x-56 you should see the graph taking a dip at this point.

3 0
3 years ago
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