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guapka [62]
2 years ago
9

What is the probability of picking a blue marble and rolling an odd number?

Mathematics
1 answer:
Paladinen [302]2 years ago
6 0

Answer:

3/6 chance.

Step-by-step explanation:

To roll an odd number on a six sided dice (Guessing it's six sided) you would have to roll either a 1, 3, or 5.  That would it 3 choices.  You get the six by taking the amount (like the amount of sides on the dice).  You would then have a 3/6 chance of rolling an odd number.

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Can someone help me! Please
likoan [24]

Answer:

4c - 2

Step-by-step explanation:

Add up all the terms to find the perimeter.

2c + 2(c - 1)

2c + 2c - 2

4c - 2

Therefore, the perimeter is 4c - 2.

5 0
3 years ago
-7 2/3 + ( -5 1/2 ) + 8 3/4 = ? <br><br> A: -4 5/12 <br> B: -21 11/12 <br> C: -4 2/3 <br> D: 6 7/12
frez [133]

Answer:

-4 5\12

Step-by-step explanation:

Identify the Least Common Denominator, 12, then just simply evaluate.

8 0
3 years ago
Arithmetic of functions
Rzqust [24]

Its B.

If f(x)=4x+1 and g(x)=x^2-5 then, (\frac{g}{f})(x)=\frac{x^2-5}{4x+1} and x\neq-\frac{1}{4} because if x were -\frac{1}{4} then you would have division by 0.

Hope this helps.

5 0
2 years ago
Rockwell hardness of pins of a certain type is known to have a mean value of 50 and a standard deviation of 1.8. (Round your ans
Alenkinab [10]

Answer:

a) 0.011 = 1.1% probability that the sample mean hardness for a random sample of 17 pins is at least 51

b) 0.0001 = 0.1% probability that the sample mean hardness for a random sample of 45 pins is at least 51

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 50, \sigma = 1.8

(a) If the distribution is normal, what is the probability that the sample mean hardness for a random sample of 17 pins is at least 51?

Here n = 17, s = \frac{1.8}{\sqrt{17}} = 0.4366

This probability is 1 subtracted by the pvalue of Z when X = 51. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{51 - 50}{0.4366}

Z = 2.29

Z = 2.29 has a pvalue of 0.9890

1 - 0.989 = 0.011

0.011 = 1.1% probability that the sample mean hardness for a random sample of 17 pins is at least 51

(b) What is the (approximate) probability that the sample mean hardness for a random sample of 45 pins is at least 51?

Here n = 17, s = \frac{1.8}{\sqrt{45}} = 0.2683

Z = \frac{X - \mu}{s}

Z = \frac{51 - 50}{0.0.2683}

Z = 3.73

Z = 3.73 has a pvalue of 0.9999

1 - 0.9999 = 0.0001

0.0001 = 0.1% probability that the sample mean hardness for a random sample of 45 pins is at least 51

8 0
3 years ago
50 PTS!!!
nydimaria [60]

Answer:

the data of the cubic

as it the distance between the two integers closed under addition

5 0
2 years ago
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