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Mars2501 [29]
3 years ago
15

HELP PLS WHAT DO I PUT IN THE BLANKS

Mathematics
1 answer:
pickupchik [31]3 years ago
5 0

Answer:

The answer is -7. This equation only has one solution. It makes the equation -2 = -2.  

For the second part, you can use a number like 7 and then that would make it be 2 = -2. Hope this Helps!

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Is (1, 4) a solution to the equation y = 7x?
VashaNatasha [74]

Answer:

No

Step-by-step explanation:

y=7x

4=7(1)

4=7

This is not a true statement.

4 0
4 years ago
If 1 egg boiled 3 minutes then6 eggs r boiled in..................min​
AleksAgata [21]

count by 3,

3 6 9 12 15 18

18 minutes for 6 eggs.

4 0
3 years ago
Read 2 more answers
Will give brainliest !!
lesya692 [45]

Answer:

[B]=2

Step-by-step explanation:

B=\left[\begin{array}{ccc}3x-5&-3+2y\\11-3x&2y-5\end{array}\right]

With x=3 and y=4

B=\left[\begin{array}{ccc}3(3)-5&-3+2(4)\\11-3(3)&2(4)-5\end{array}\right]

B=\left[\begin{array}{ccc}9-5&-3+8\\11-9&8-5\end{array}\right]

B=\left[\begin{array}{ccc}4&5\\2&3\end{array}\right]

solving the determinant of matrix B

[B]=\left[\begin{array}{ccc}4&5\\2&3\end{array}\right]=(4.3-5.2)=(12-10)=2

8 0
3 years ago
Read 2 more answers
I’ll give you a lot of points for this
ivann1987 [24]

Answer:

2. (3,4)

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
4(3xy^4)^3/(2x^3y^5)^4
myrzilka [38]

Answer:

\frac{4\left(3xy^4\right)^3}{\left(2x^3y^5\right)^4}=\frac{27}{4x^9y^8}

Step-by-step explanation:

Given the expression

\:\:\frac{4\left(3xy^4\right)^3}{\left(2x^3y^5\right)^4}

solving the expression

\:\:\frac{4\left(3xy^4\right)^3}{\left(2x^3y^5\right)^4}=4\cdot \:\frac{\left(3xy^4\right)^3}{\left(2x^3y^5\right)^4}

             =4\:\frac{27x^3y^{12}}{16x^{12}y^{20}}

              =4\cdot \frac{3^3}{2^4x^9y^8}

The multiply fractions are defined as

\:a\cdot \frac{b}{c}=\frac{a\:\cdot \:b}{c}

so the expression becomes

                =\frac{3^3\cdot \:4}{2^4x^9y^8}

                =\frac{3^3\cdot \:2^2}{2^4x^9y^8}

                =\frac{3^3}{2^2x^9y^8}

Refining

                 =\frac{27}{4x^9y^8}

Therefore,

\frac{4\left(3xy^4\right)^3}{\left(2x^3y^5\right)^4}=\frac{27}{4x^9y^8}            

8 0
3 years ago
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