Number of ways in which the 3 can be selected from 13 = 286
Step-by-step explanation:
Step 1:
Number of books considered by the textbook search committee = 13
Number of books selected from this 13 = 3
We need to determine number of ways in which the 3 can be selected from the 13
Step 2 :
The order of the 3 books selected does not matter. So,
Number of ways in which the 3 books can be selected from 13 books = C(13,3) = ![\frac{13!}{10! . 3!}](https://tex.z-dn.net/?f=%5Cfrac%7B13%21%7D%7B10%21%20.%203%21%7D)
=![\frac{ 13 . 12 .11 . 10!}{10! . 3! }](https://tex.z-dn.net/?f=%5Cfrac%7B%2013%20.%2012%20.11%20%20.%2010%21%7D%7B10%21%20.%203%21%20%7D)
=
= 286
Step 3 :
Answer :
Number of ways in which the 3 can be selected from 13 = 286
I THINK YOU FORGOT TO POST THE COMPLETE Q.
Answer:
971.91
Step-by-step explanation:
you take 107.99 and multiply it by 9 and you will get 971.91
Answer:
10
Step-by-step explanation:
You use the distance formula by finding the x and y difference, and you get 8, for x value, 6 for y value, and then you use Pythagorean theorem to get 10 for AB.
Creo que es A si no es porfavor dime.