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LiRa [457]
3 years ago
6

One month Isabel rented 5 movies and 2 video games for a total of $18. The next month she rented 3 movies and 8 video games for

a total of $55. Find the
rental cost for each movie and each video game.

-Rental cost for each movie:

-Rental cost for each video game:
Mathematics
1 answer:
Elis [28]3 years ago
6 0

Answer:

video=$6.5

movie=$1

Step-by-step explanation:

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Step-by-step explanation:

Your checkmarks are in the right places. So the answers are correct that you have chosen.

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How much will it cost to fill up an empty 12-gallon take if gasoline costs $1.1599 per gallon
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13.9188 dollars

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1.1599 * 12 = 13.9188

8 0
3 years ago
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Find the angel x in d diagram above with a well structured solution.<br><br>Thanks​
Tom [10]

Step-by-step answer:

Please refer to attached image.

1. Quad PQRS is cyclic (all vertices on the same circle), so opposite angles are supplementary, meaning

  that

  angles QPS and QRS are supplementary =>

  QPS+QRS=180   =>

  QRS = 180 - 74 = 106

2. Triangle RSQ is isosceles with RS=RQ =>

   angles RSQ and RQS are congruent.

3. Angle RSQ = (180 - 106) /2 = 74 / 2  = 37

4. QP is a diameter => angle QSP is a right-angle.

5. From (3) and (4) above,

  angle RSP = 37+90 = 127

6. Since PQRS is cyclic, angles RQP  and RSP are supplementary =>

   RQP+RSP = 180   =>

   x + 127 = 180   =>

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5 0
3 years ago
The two-way table shows the number of books of each type in Eliza's home ​what is the probability that a randomly selected refer
Salsk061 [2.6K]

Answer:

B. 0.4

Step-by-step explanation:

Use the definition of the probability

Pr=\dfrac{\text{Number of all favorable outcomes}}{\text{Number of all possible outcomes}}

You have to find the probability that a randomly selected reference book is hard cover. Hence, from the table

  • Number of all possible outcomes = Number of Reference books = 25
  • Number of all favorable outcomes = Number of Hardcover Reference books = 10

So, the probability is

Pr=\dfrac{10}{25}=\dfrac{40}{100}=0.4

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3 years ago
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Douglas is placing strings of lights around the edge of a circular patio with a diameter of 7.5 m. The lights are in lengths of
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Circumference of circular path=pi*d^2/4
=44.156
length of light=1.45

light needed=44.156/1.45
=31 approx
8 0
3 years ago
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