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cupoosta [38]
3 years ago
15

Explain whether the following given sets are closed under addition:

Mathematics
1 answer:
Ivan3 years ago
7 0

Answer:

Step-by-step explanation:

a) Yes.

\forall\ a,b\ \in\ B,\ a+b\in B\ (since\ 0+0=0)

b) Yes

W=\{0,1,2,3,..,\}\ (whole\ numbers)\\\forall\ a,b\ \in\ 3W,\ a+b\in 3W\\since:\\a\ \in\ 3W \Longrightarrow\ \exists\ k_1\in W | a=3*k_1\\\\b\ \in\ 3W \Longrightarrow\ \exists\ k_2\in W | b=3*k_2\\\\a+b=3*k_1+3*k_2=3*(k_1+k_2) \in 3W\\

c) Yes

\forall n\ \in\ \mathbb{N}: \Longrightarrow\ n+1 \in\ \mathbb{N}\\

d) No

3\in V , 3+3=6\notin V\\

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What is another way to name ∠MNO ?
katrin [286]

Alright, lets get started.

Please take a look to the diagram I have attached.

The base side is ON

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We could say angle MNO as angle N.

We could day it as angle ONM also.

So, the answer is ∠ N and ∠ONM.   :  Answer

Hope it will help :)


7 0
3 years ago
I need help! Please help me
insens350 [35]

Answer:

x = 3.6

Step-by-step explanation:

By the Postulate of intersecting chords inside a circle.

x \times 5 = 3 \times 6 \\ 5x = 18 \\ x =  \frac{18}{5}  \\ x = 3.6 \\

5 0
3 years ago
What is the expressions to 2 2 _ 7
castortr0y [4]

Answer:

its an equivalent equation

Step-by-step explanation:

are algebraic equations that have identical solutions or roots. Adding or subtracting the same number or expression to both sides of an equation produces an equivalent equation. Multiplying or dividing both sides of an equation by the same non-zero number produces an equivalent equation.

3 0
3 years ago
① 5J+2S =12.20 ② 5J+ 10S =15.80 elimination method
hram777 [196]

Answer:

<h2>S = 9/20</h2><h2>J = 113/50</h2>

Step-by-step explanation:

5J +2S =12.20 ........(1)\\5J+10S=15.80......(2)\\Multiply \:equation \:(1)\:by\:the\:coefficient\:of\:x\:in equation\:(2)\\\\Multiply\:equation(2)\: by\: the\: coefficient\:of \:x\: in \:equation (1)\\\\5J +2S =12.20 ........(1) \times 5\\5J+10S=15.80......(2)\times 5\\\\25J+10S=61......(3)\\25J+50S = 79......(4)\\Subtract\:equation\:(4)\:from\: equation\: (3)\\-40S =-18\\\frac{-40S}{-40}=\frac{-18}{-40}\\  S = 9/20\\

Substitute \:9/20\:for \:x \:in\:equation\:(1)\:or \:equation\:(2)\\5J+2S = 12.20\\5J +2(9/20) =12.20\\5J +9/10=12.20\\5J=12.20-9/10\\5J=113/10\\Cross-Multiply\\50J = 113\\J = 113/50

4 0
3 years ago
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