OKAY I NEED HELP. DONT MIND THE FACT I HAVED IT ANSWERED IT DOESNT SEEM TO LET ME TAKE IT OFF BUT I NEED HELP PLS D:::
2 answers:
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Answer:
Step-by-step explanation:
We are given that,
The fall of the acorn is represented by the function,
Equating S(t) to 0 gives,
i.e.
i.e.
i.e.
Since, time cannot be negative.
So, i.e. 1.25 seconds is the time when the acorn will reach the ground.
Thus, from the figure below, we see that,
The interval in which the acorn is in the moving air is .
Answer:
Option (C)
Step-by-step explanation:
In the given circle, AB is a chord passing through the center O.
Therefore,chord AB is a diameter of the circle and OC is the radius.
AO = OB = OC
OC⊥AB, and length of OC = 7 cm
By applying Pythagoras theorem in right ΔBOC,
BC² = OC² + OB²
BC =
=
=
≈ 9.9 units
Therefore, Option (C) will be the answer.
Answer:
Step-by-step explanation:
= x - 5 ( x ≥ 3 )
( )² = ( x - 5 )²
x - 3 = x² - 10x + 25
x² - 11x + 28 = 0
(x - 4)(x - 7) = 0
= 7
= 4
Check the answer:
1). x = 7
= 7 - 2
√4 = 2
2 = 2
2). x = 4
= 4 - 5
1 = - 1 (False statement) ⇒ x = 4 is an extraneous solution.
