Answer:
13.05
Step-by-step explanation:
<span>[68,100]
This will allow you to get a B score.
To solve find the medium by adding the values divided by 4, solve for the unknown of the final exam, with the minimum value equalling 80, this will give you 68.</span>
Since there are 2 rows with 8 in each row the answer is 16 chairs
Answer:
123
Step-by-step explanation:
if the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadth
A) You just fill in 0 for w in the problem and anything raised to the power of 0 is 1, so 230(1) is 230, and that is the old factory and at 0 for the new it is at 190. Subtract then explain why you did what you did.
B) I believe what they are asking for you to do, is you can take each week from the new factory and subtract it and find the equation for the new factory, you already know the growth rate for the old factory= 230(1.1)^w.
C) You take your old factory's equation and plug in numbers until one of them is greater at the new factory. Here it is the 5th week.
