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german
2 years ago
7

AABC is reflected across the x-axis and then dilated by a factor of 2 using the

Mathematics
1 answer:
Hitman42 [59]2 years ago
7 0

The transformation of A is A' = (8, -3)

<h3>How to determine the transformation?</h3>

From the graph, we have:

A = (3,1)

The scale factor and the center of dilation are given as:

k = 2

(a,b) = (-2,1)

The rule of reflection across the axis is:

(x,y) ⇒ (x,-y)

So, we have:

A' = (3,-1)

The rule of dilation is represented as:

(x,y) ⇒ (k(x - a) + a, k(y - b) + b)

So, we have:

A' = (2(3 + 2) - 2, 2(-1 - 1) + 1)

Evaluate

A' = (8, -3)

Hence, the transformation of A is A' = (8, -3)

Read more about transformation at:

brainly.com/question/4289712

#SPJ1

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Is the relation shown in the table below a function? Explain.
jek_recluse [69]

Answer

No

Step-by-step explanation:

it is not a function because 9 and three are a pair but so are 27 and 3. that makes it not a function

4 0
3 years ago
You need 320 mL of a 85% alcohol solution. On hand, you have a 60% alcohol mixture. How much of the 60% alcohol mixture and pure
Radda [10]

Answer:

Step-by-step explanation:

If we let x = the amount of 5% solution and y = the amount of pure alcohol, we can set up that

.05x+y is the amount of alcohol in our resulting mixture, and x+y is the total amount in our resulting mixture (which we know is 380)

so we also know that:

(.05x+y)/380 = .6

If we simplify this we come up with:

.05x+y=228

and we know x+y=380

If we solve this as a system of equations, we will find that:

x=160 ml

y=220 ml

5 0
3 years ago
What is the percentage of 350 over 100
Ivahew [28]
350/100 = 350%
350% is the percentage of 50 over 100
4 0
3 years ago
How I can write 680,705 in expanded form
KatRina [158]
600,000+80,000+700+5
5 0
3 years ago
Read 2 more answers
The equation of a circle is (x + 6)^2 + (y - 4)^2 = 16. The point (-6, 8) is on the circle.
pantera1 [17]

Answer:

y = 8 is the equation of tangent.

Step-by-step explanation:

The equation of the tangent to the circle at (-6,8) is of the form:

y = mx + c

where m is the slope of the tangent and c is the y-intercept.

The point (-6,8) lies on the circle and the tangent line as well.

Hence (-6,8) satisfies the line equation:

8 = m(-6) + c ⇒ c-6m = 8 -------------1

We know that slope of two perpendicular lines are related as:

m_{1}\times m_{2}=-1

At any point on the circle, the normal line at a point is always perpendicular to the tangent line at that point.

Hence :

m_{normal} \times m_{tangent}=-1

We can find the slope of the normal at point (-6,8) as it passes through the centre of the circle (-6,4) by using the two-points formula for slope.

m=\frac{y_2-y_1}{x_2-x_1}

         =\frac{8-4}{-6+6}

          = ∞

Slope of the normal is infinity and hence slope of tangent is -1/∞ = 0

Hence m=0

Putting m=0 in equation 1 we get:

c = 8

The equation of tangent line at (-6,8) is:

y = 8

6 0
3 years ago
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