Answer:
(x+1)^3
Step-by-step explanation:
this question seems easy enough
Answer:
Step-by-step explanation:
#include <stdio.h>
int main()
{
int num1, num2, flag_var, i, j;
/* Ask user to input the from/to range
* like 1 to 100, 10 to 1000 etc.
*/
printf("Enter two range(input integer numbers only):");
//Store the range in variables using scanf
scanf("%d %d", &num1, &num2);
//Display prime numbers for input range
printf("Prime numbers from %d and %d are:\n", num1, num2);
for(i=num1+1; i<num2; ++i)
{
flag_var=0;
for(j=2; j<=i/2; ++j)
{
if(i%j==0)
{
flag_var=1;
break;
}
}
if(flag_var==0)
printf("%d\n",i);
}
return 0;
}
Given the point U and point V, the midpoint between of the line segment UV is ( 0, -5/2 ).
<h3>What is the midpoint of line UV?</h3>
The midpoint formula is used to find the midpoint of a line segment.
It is expressed as;
[ (x₁ + x₂ )/2 , (y₁ + y₂ )/2 ]
Given the data in the graph,
Point U = ( 3, -1 ) and Point V = ( -3, -4 )
- x₁ = 3
- x₂ = -3
- y₁ = -1
- y₂ = -4
We substitute into the formular above.
[ (x₁ + x₂ )/2 , (y₁ + y₂ )/2 ]
[ (3 + (-3) )/2 , ( (-1) + (-4) )/2 ]
[ 0/2, (-1-4)/2 ]
[ 0/2, -5 /2 ]
( 0, -5/2 )
Given the point U and point V, the midpoint between of the line segment UV is ( 0, -5/2 ).
Learn more about midpoint of line segment here: brainly.com/question/13792156
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