The first to do is to isolate the constant, k, to one side. The rate expression would then be:
k = rate/ <span>[A][B]^2
This constant, k, will be the same for the given reaction at a certain temperature. Then, we can relate a second rate to this reaction.
</span>rate1/ [A1][B1]^2 = rate2/ [A2][B2]^2
First question:
0.0810 / [A1][B1]^2 = rate2/ <span>[A2/2][3B2]^2
rate2 = (</span>0.0810 [A2/2][3B2]^2 )/ [A1][B1]^2
rate2 = 0.3645 M/s
Second Equation:
0.0810 / [A1][B1]^2 = rate2/ <span>[A2/2][3B2]^2
rate2 = (</span>0.0810 [3A2][B2/2]^2 )/ [A1][B1]^2
<span>rate2 = 0.0608 M/s</span>
I think the answer is magnetic field?
Answer : The molarity of an acetic acid solution is, 0.0338 M
Explanation :
Formula used :
where,
are the molarity and volume of acetic acid.
are the molarity and volume of NaOH.
We are given:
Putting values in above equation, we get:
Hence, the molarity of an acetic acid solution is, 0.0338 M
<h3>
Answer:</h3>
147.05 g/mol
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
CuClO₃
<u>Step 2: Find MM</u>
Molar Mass of Cu - 63.55 g/mol
Molar Mass of Cl - 35.45 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of CuClO₃ - 63.55 + 35.45 + 3(16.00) = 147.05 g/mol
The main use of litmus is to test whether a solution is acidic or basic. Blue litmus paper turns red under acidic conditions and red litmus paper turns blue under basic or alkaline conditions, with the color change occurring over the pH range 4.5–8.3 at 25 °C (77 °F).
