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3 years ago

What are the three steps or formation of ionic compounds strontium and oxygen

Chemistry

1 answer:

Roman55 [17]3 years ago

8 0

<h2>The three steps or formation of ionic compounds strontium and oxygen</h2>

Explanation:

Chemical bond

It is the linkage between two or more atoms in a molecule.

Cause of bond formation

The atoms combine with one another to achieve noble gas configuration. By doing so they become stable.

Atom can achieve noble gas configuration

By loosing one or more e’s.

By gaining one or more e’s.

By sharing one or more e’s.

Types of CHEMICAL BONDS

IONIC BOND (or electrovalent)

COVALENT BOND

Ionic bond

It is the Bond formed by transfer of electrons from one atoms to another.

It is formed when one atom donate electron & other accept electrons to achieve stable confugration.

NOTE: it is always formed between metal a non-metal.

Examples :-

* Formation of sod. Chloride as we know their atomic no., are

Na Cl

11 17 (atomic numbers of combining atoms )

. 2, 8, (1) 2, 8, (7) (Electronic configuration )

Metal non-metal (bond will be ionic)

We’ll start with metal

Na - 1 e- → Na+

Cl + 1e- → Cl-

Na + Cl → Na⁺ Cl⁻

NaCl

Similarly ,for strontium and oxygen

Sr ⁸⁺ O⁸⁻

SrO(Strontium oxide )

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$m_2$ = mass of coffee = 180 g

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$T_1$ = temperature of aluminium = $24^oC$

$T_2$ = temperature of coffee = $85^oC$

$c_1$ = specific heat of aluminium = $0.80J/g^oC$

$c_2$ = specific heat of coffee= $4.186 J/g^oC$

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$45 g\times 0.80J/g^oC\times (T_{final}-24^oC)=-[180 g\times 4.186J/g^oC\times (T_{final}-83^oC)]$

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80.30 °C is the final temperature.

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So, is our final temperature of both aluminium and coffee that is 80°C less than initial temperature of coffee and more than the initial temperature of the aluminum.

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