Answer:
2
Step-by-step explanation:
GCF stands for the "greatest common factor." Therefore because 2 can go into both 2 and 4 evenly, it is the GCF.
Answer:
Step-by-step explanation:
Given that,
Outcomes Heads= 4heads and
Outcomes Tails= 6tails
Total outcome of events n=10
Probability of head in is first throw is, the is the outcome of head divide by the total possible outcomes
P(Head in first throw)=4/10
P(H)=2/5
P(H) = 0.4
P(H) =40%
Answer:
Correct option is (C).
The possible value of the <em>p</em>-value for a one-tailed test are 0.22 and 0.78.
Step-by-step explanation:
The <em>p</em>-value is the probability of acquiring a result as extreme as the observed result, assuming the null hypothesis statement is true.
The <em>p</em> value of a test is:
Left-tailed test: 
Right-tailed test: 
.
Here,
TS = Test statistic
ts = computed value of the test statistic.
The two-tailed <em>p</em>-value is: 
or 
.
The <em>p</em>-value of the two tailed test is, 0.44.
Compute the <em>p</em>-value for one-tailed test a follows:
Thus, the possible value of the <em>p</em>-value for a one-tailed test are 0.22 and 0.78.
The correct option is (C).
Answer:
there are no values of S
that make the equation true.
No solution
Step-by-step explanation:
Answer:
h = height reached
-16 t^2 = 1/2 g t^2 where g = 32 ft/sec^2
v t = height due to original vertical speed v
s = initial height
1. -45 = -16 t^2 + 62 t + 0 measuring height from original height
solving quadratic
2. t = 4.5 sec
3. time to reach max height = v / g = 62/32 = 1.94 sec
H (above release point) = -16 (1.94^2) + 62 * 1.94 = 60 ft
4. 2 * 1.94 = 3.88 solved in part 3
5. 1.94 solved on part 3
Check: time to fall 60 + 45 ft = 105 ft
105 = 1/2 g t^2
t = (210 / 32)^1/2 = 2.56 sec
total time = 2.56 * 1.94 = 4.5 sec time to fall + rise time
-45 = -16 * 4.5^2 + 62 * 4.5
-45 = -324 + 279 = -45 checking time to reach -45 feet using given equation
