3 years ago

The first term of a geometric sequence is 6 and the common ratio is -4 find the 6th term

Mathematics

1 answer:

mart [117]3 years ago

6 0

R = - 4
t1 = 6

tn = a1*r^(n - 1)
t6 = 6 * (-4)^(6 - 1)
t6 = 6 * (-4)^5
t6 = 6 * (-1024)
t6 = -6144

You might be interested in

Did Meg make it home on time if she spent 22 minutes at the library. 38 minutes at her grandmas house. She walked for 17 minutes

Tomtit [17]

Not enough info to answer

4 0

3 years ago

What is the expression in radical form?<br><br> (4x3y2)310

sertanlavr [38]

Given:

Consider the given expression is

$(4x^3y^2)^{\frac{3}{10}}$

To find:

The radical form of given expression.

Solution:

We have,

$(4x^3y^2)^{\frac{3}{10}}=(2^2)^{\frac{3}{10}}(x^3)^{\frac{3}{10}}(y^2)^{\frac{3}{10}}$

$(4x^3y^2)^{\frac{3}{10}}=(2)^{\frac{6}{10}}(x)^{\frac{9}{10}}(y)^{\frac{6}{10}}$

$(4x^3y^2)^{\frac{3}{10}}=(2)^{\frac{3}{5}}(x)^{\frac{9}{10}}(y)^{\frac{3}{5}}$

$(4x^3y^2)^{\frac{3}{10}}=\sqrt[5]{2^3}\sqrt[10]{x^9}\sqrt[5]{y^3}$ $[\because x^{\frac{1}{n}}=\sqrt[n]{x}]$

$(4x^3y^2)^{\frac{3}{10}}=\sqrt[5]{8y^3}\sqrt[10]{x^9}$ $[\because x^{\frac{1}{n}}=\sqrt[n]{x}]$

Therefore, the required radical form is $\sqrt[5]{8y^3}\sqrt[10]{x^9}$ .

8 0

3 years ago

Math again sadly i need help on

dalvyx [7]

Answer:

13x+12

Step-by-step explanation:

27x-14x=13

+12 because there is nothing else there

5 0

3 years ago

Read 2 more answers

Hello can anyone give me the full answer to this step by step?

Andre45 [30]

Answer:

1. f = 16 degrees

2. h = 10 degrees

Step-by-step explanation:

1. f = (180 - 67+46 - 4) / 4

2. h = (180 - 60 + 90) / 3

5 0

2 years ago

Read 2 more answers

2x+8y=5<br> 24x-4y=-15<br> the solution to the system is ( , ) ( , )

kicyunya [14]

[-½, ¾]; use either "Substitution" or "Elimination" to do this, and you'll see that this answer is correct.

3 0

3 years ago