Answer:
love you sweety
Step-by-step explanation:
love u sweety sweety
Answer:
15 seconds
Step-by-step explanation:
If you make a table of values for the dog and the squirrel using d = rt, then the rates are easy: the dog's rate is 150 and the squirrel's is 100. The t is what we are looking for, so that's our unknown, and the distance is a bit tricky, but let's look at what we know: the dog is 200 feet behind the squirrel, so when the dog catches up to the squirrel, he has run some distance d plus the 200 feet to catch up. Since we don't know what d is, we will just call it d! Now it seems as though we have 2 unknowns which is a problem. However, if we solve both equations (the one for the dog and the one for the squirrel) for t, we can set them equal to each other. Here's the dog's equation:
d = rt
d+200 = 150t
And the squirrel's:
d = 100t
If we solve both for t and set them equal to each other we have:

Now we can cross multiply to solve for d:
150d = 100d + 20,000 and
50d = 20,000
d = 400
But we're not looking for the distance the squirrel traveled before the dog caught it, we are looking for how long it took. So sub that d value back into one of the equations we have solved for t and do the math:

That's 1/4 of a minute which is 15 seconds.
Answer: 11 hours and 25 minutes
Step-by-step explanation:
Since she left at 7:10 am you can add 50 minutes and you will get 8, then all the way to 6 pm is 10 hours. Now you just have 50 and 35 minutes that you havent added to the total yet so when you add those two together you get 85. But there isnt 85 minutes in a hour so you would have yo break it down and you would get 1 hour and 25 minutes. Add 1 hour and 25 minutes to 10 hours and you get 11 hours and 25 minute. I hope that helps!
Sorry if you didnt under stand my explanation.
Answer:
it's 2
Step-by-step explanation:
hope this helps you.