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3 years ago

15) You are buying balloons and cupcakes for your friend's

Mathematics

1 answer:

inysia [295]3 years ago

5 0

Answer:

variable is number of balloons

b = balloons

b+10 = cupcakes

85 = 2b + 5b + 50 = 7b + 50

Step-by-step explanation:

#cupcakes = 10 + b #balloons

total cost $85 = ($2 x b) + $5 x (b + 10)

balloons cupcakes

85 = 2b + 5b + 50 combine terms and subtract 50 from both sides of =

35 = 7b then divide both sides by 7

5 balloons

15 cupcakes

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-[tex]-8\9 + 1/5+ -8/15

TiliK225 [7]

Answer:

$-\frac{11}{9}$ , OR $-1\frac{2}{9}$ , OR -1.2

Step-by-step explanation:

$-\frac{8}{9}+\frac{1}{5}+(-\frac{8}{15})$ When there is a (+) in front of an expression in parentheses, the expression remains the same

$-\frac{8}{9}+\frac{1}{5}-\frac{8}{15}$ Calculate the sum or difference

$-\frac{11}{9}$

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3 years ago

What is the value of x? x+58=6 Enter your answer in the box in simplest form.

Stolb23 [73]

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Bumek [7]

Answer:

Dimensions of rectangle:

Length =6 yards

Width=3 1/3 yards

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Step-by-step explanation:

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When we match this triangle with another right triangle to make the rectangle is another right triangle with sides 6 yards and 3 1/3 yards.

I'll upload the file for work.

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3 years ago

8/x-5 - 9/x-4 = 5/x^2-9x+20

adelina 88 [10]

If you're using the app, try seeing this answer through your browser: brainly.com/question/2752942

_______________

Solve the equation:

$\mathsf{\dfrac{8}{x-5}-\dfrac{9}{x-4}=\dfrac{5}{x^2-9x+20}\qquad\qquad(x\ne 5~and~x\ne 4)}$

Reduce the fractions at the left side so that they have the same denominator:

$\mathsf{\dfrac{8(x-4)}{(x-5)(x-4)}-\dfrac{9(x-5)}{(x-4)(x-5)}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32}{x^2-4x-5x+20}-\dfrac{9x-45}{x^2-4x-5x+20}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32}{x^2-9x+20}-\dfrac{9x-45}{x^2-9x+20}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32-(9x-45)}{x^2-9x+20}=\dfrac{5}{x^2-9x+20}}$

Numerators must be equal:

$\mathsf{8x-32-(9x-45)=5}\\\\
\mathsf{8x-32-9x+45=5}\\\\
\mathsf{8x-9x=5+32-45}\\\\
\mathsf{-x=-8}\\\\
\mathsf{x=8}\quad\longleftarrow\quad\textsf{this is the solution.}$

I hope this helps. =)

Tags: <em>rational equation fraction solution algebra</em>

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