Considering 32 outside the square root .
![(8+5 \sqrt x -98) -(3+6\sqrt x-32)](https://tex.z-dn.net/?f=%20%288%2B5%20%5Csqrt%20x%20-98%29%20-%283%2B6%5Csqrt%20x-32%29%20)
Here we have to combine like terms, and like terms are 8 , 98 ,3, 32 and 5 square root x and 6 square root x .
We need to remove the parenthesis and since there is a minus sign outside the second parenthesis , so we have to flip the sign of the terms of second parenthesis. THat is
![8-98-3+32+5 \sqrt x -6 \sqrt x](https://tex.z-dn.net/?f=%208-98-3%2B32%2B5%20%5Csqrt%20x%20-6%20%5Csqrt%20x%20)
=![-61 - \sqrt x](https://tex.z-dn.net/?f=%20-61%20-%20%5Csqrt%20x%20)
And that's the final answer .
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0.72840984877 is the answer :)
Answer:
9 ÷ (x + y)
This is not specific
Step-by-step explanation:
Answer:
C. (0, 10)
Step-by-step explanation: