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3 years ago

An edge of a square has vertices with coordinates (a, b) and (-a,- b). Write expre

Mathematics

1 answer:

Tema [17]3 years ago

6 0

Answer:

Step-by-step explanation:

Value of the edge of the square=d

$d^2=(a^2+b^2+(-a)^2+(-b)^2=2(a^2+b^2)\\\\d=\sqrt{2(a^2+b^2)}\\\\Perimeter=4*d=4*\sqrt{2(a^2+b^2)}\\\\Area=d^2=2(a^2+b^2)\\$

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Find the values of X and Y. Write your answers in simplest form.<br> X=__<br> Y=__

uranmaximum [27]

Hope this helps!
Anymore doubt, ask away

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3 years ago

How many terms does the polynomial have?

ollegr [7]

Answer: 4

Step-by-step explanation:

There are 4 terms, $p^3,4pq^2,q^2,3q$

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3 years ago

Add the following polynomials

Yuri [45]

Answer is x² + 2x + 5

<u>Step-by-step explanation:</u>

Step 1:

Add the two polynomials

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3 years ago

Read 2 more answers

jamal's school is having a bake sale today at lunch and he agreed to bring four dozen cupcakes in for sale. to catch his bus he

Vesna [10]

Answer:

They will finish in time for Jamal to catch the bus.

Step-by-step explanation:

Jamal agreed to bring four dozen i.e. 48 cupcakes in for sale.

He started icing cupcakes at 7:40 a.m. at a rate of 3 cupcakes per minute up to 7:50 a.m. that is the time when he needs to be out of his house to catch his bus.

So, with in this 10 minutes (7:40 a.m. to 7:50 a.m.) he would be able to make (10 × 3) = 30 cupcakes.

Now, at 7:44 his older sister started icing cupcakes too. she iced them at a rate of 4 cupcakes per minute.

So, in this 6 minutes (7:44 a.m. to 7:50 a.m.) she will be able to make (4 × 6) = 24 cupcakes.

Therefore, in total Jamal will be able to made (30 + 24) = 54 cupcakes.

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3 years ago

Which expression correctly simplifies (312415)56?

Andreyy89

Answer:

$\sf C)\quad \large\text{$\dfrac{3^{\frac{5}{12}}}{4^{\frac{1}{6}}}$}$

Step-by-step explanation:

Given expression:

$\large\text{$\left(\dfrac{3^{\frac{1}{2}}}{4^{\frac{1}{5}}}\right)^\frac{5}{6}$}$

$\textsf{Apply exponent rule} \quad \left(\dfrac{a}{b}\right)^c=\dfrac{a^c}{b^c}:$

$\large\text{$\implies \dfrac{\left(3^{\frac{1}{2}}\right)^\frac{5}{6}}{\left(4^{\frac{1}{5}}\right)^\frac{5}{6}}$}$

$\textsf{Apply exponent rule} \quad (a^b)^c=a^{bc}:$

$\large\text{$\implies \dfrac{3^{(\frac{1}{2}\times \frac{5}{6})}}{4^{(\frac{1}{5}\times \frac{5}{6})}}$}$

Simplify:

$\large\text{$\implies \dfrac{3^{\frac{5}{12}}}{4^{\frac{1}{6}}}$}$

Learn more about exponent rules here:

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2 years ago