Yes hope this helps man!!
Answer:
The car must have a speed of 25 kilometres per hour to stop after moving 7 metres.
Step-by-step explanation:
Let be 
, where 
is the stopping distance measured in metres and 
is the speed measured in kilometres per hour. The second-order polynomial is drawn with the help of a graphing tool and whose outcome is presented below as attachment.
The procedure to find the speed related to the given stopping distance is described below:
1) Construct the graph of 
.
2) Add the function 
.
3) The point of intersection between both curves contains the speed related to given stopping distance.
In consequence, the car must have a speed of 25 kilometres per hour to stop after moving 7 metres.
2 out of 50 were tagged.
Divide 2 by 50:
2/50 = 0.4 ( This is 4% of the fish were tagged).
Now divide the number of fish caught by the percentage that were tagged:
50 / 0.04 = 1250
The number of fish in the pond is C. 1250
Answer:
1. 5700mg
2. 1000cm
3. 0.0453m
4. 37.5 kg/L
Step-by-step explanation:
1. 1gram (g) =1000milligrams(mg)
5.70×1000=5700mg
2. 1 m= 100cm
10×100=1000cm
3. 1000mm=1m
45.3/1000=0.0453m
4. 1000g=1kg
37.5/1000=0.0375
1000ml=1L
1ml= 1/1000= 0.001L
0.0375/0.001= 37.5 kg/L
Answer:
48 minutes
Step-by-step explanation:
Given that:
Time taken by Janet = 3 hours
Janet's rate = 1/3 job / hour
Time taken by Garry = 2 hours
Garry's rate = 1/2
Rate of working together :
1/3 + 1/2 = (2 + 3) /6 = 5/6 job/hour
If Janet works for one hour before Garry joins ;
1/3 of the job has been done by Janet
1 - 1/3 = 2/3 of the job left
Hence to finish the job together, it will take :
Fraction of JOB left ÷ rate of working together
(2/3 ÷ 5/6)
= 2 /3 * 6/5
= 12 / 15
= 4 / 5 hours
To minutes
(4/5) * 60
= 240/5
= 48 minutes
