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il63 [147K]
3 years ago
6

A bakery sold a total of 3028 coffee buns and blueberry buns. 1560 more coffee buns were sold than the blueberry buns. How many

coffee buns did the bakery sell?
P.S. No algebra to be used here as it is a grade 4th question!
Mathematics
1 answer:
Natali [406]3 years ago
7 0

Answer:

\large{ \tt{ -  \: HEY  \: AH~\:♡ }}

\large{ \tt{✺ \: SOLUTION}} :

  • Provided : Total sold bakery items : 3028 coffee buns and blueberry buns & 1560 more coffee buns were sold than the blueberry buns.

  • To find : Number of coffee buns the bakery sold

- First , Subtract 1560 from 3028 :

\large{ \tt{→ \: 3028 - 1560 = 1468}}

We just subtacted the number of more coffee buns from the number of told items sold which means that the number of coffee buns and the number of blueberry buns sold are equal for now. Now divide 1428 by 2 :

\large{ \tt{→ \frac{1428}{2} = 734 }}

Now - Let's get back to the second sentence of the question and add 734 & 1560 :

\large{ \tt{→ \: 734 + 1560 =  \large{ \boxed{2294}}}}

  • Hence , The bakery sold 2294 coffee buns.

- Hope this helps , oneesan! ;)

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is 3240 a perfect cube? if not then by which smallest number should 3240 be multiplied so that the product is a perfect cube?​
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<h2>3240 it's not a perfect cube.</h2><h2>The smallest number should 3240 be multiplied so that the product is a perfect cube is 15² = 225.</h2>

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Use the Prime Factorization:

\begin{array}{c|c}3240&2\\1620&2\\810&2\\405&5\\81&3\\27&3\\9&3\\3&3\\1\end{array}\\\\3240=2\cdot2\cdot2\cdot5\cdot3\cdot3\cdot3\cdot3=2^3\cdot3^3\cdot5\cdot3=(2\cdot3)^3\cdot5\cdot3=6^3\cdot5\cdot3

3240=6^3\cdot15\qquad\text{multiply both sides by}\ 15^2\\\\3240\cdot15^2=6^3\cdot15^3=3240\cdot15^2=(6\cdot15)^3=90^3

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