All categories

3 years ago

(X^3+3x^2-x+8)/(x-1)

Mathematics

1 answer:

ki77a [65]3 years ago

8 0

Here is all of the work:

You might be interested in

. Katie withdrew a total of $300 from her bank account over the last 5 weeks. How much money did she withdraw each week? Write a

Elodia [21]

Answer:

300/5=60

Step-by-step explanation:

7 0

3 years ago

What is 3/4 improper or proper or mixed

kotegsom [21]

Answer:

proper because the numerator is lower than the denominator

3 0

3 years ago

Please help with this question

yarga [219]

5654.87 Hope this helps!

4 0

1 year ago

Ariana is setting up a salt-water

trapecia [35]

Answer:

206.4

Step-by-step explanation:

we multiply 8.6*24 and get 206.4

we know this because 1 gallon is equal to 8.6 so we multiply both quantities and get 206.4

8 0

3 years ago

A horizontal trough is 16 m long, and its end are isosceles trapezoids with an altitude of 4 m, a lower base of 4 m, and an uppe

Ganezh [65]

Answer:

0.28cm/min

Step-by-step explanation:

Given the horizontal trough whose ends are isosceles trapezoid

Volume of the Trough =Base Area X Height

=Area of the Trapezoid X Height of the Trough (H)

The length of the base of the trough is constant but as water leaves the trough, the length of the top of the trough at any height h is 4+2x (See the Diagram)

The Volume of water in the trough at any time

$Volume=\frac{1}{2} (b_{1}+4+2x)h X H$

$Volume=\frac{1}{2} (4+4+2x)h X 16$

=8h(8+2x)

V=64h+16hx

We are not given a value for x, however we can express x in terms of h from Figure 3 using Similar Triangles

x/h=1/4

4x=h

x=h/4

Substituting x=h/4 into the Volume, V

$V=64h+16h(\frac{h}{4})$

$V=64h+4h^2\\\frac{dV}{dt}= 64\frac{dh}{dt}+8h \frac{dh}{dt}$

h=3m,

dV/dt=25cm/min=0.25 m/min

$0.25= (64+8*3) \frac{dh}{dt}\\0.25=88\frac{dh}{dt}\\\frac{dh}{dt}=\frac{0.25}{88}$

=0.002841m/min =0.28cm/min

The rate is the water being drawn from the trough is 0.28cm/min.

3 0

3 years ago