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Mekhanik [1.2K]
2 years ago
11

What are the areas of all these triangles? I need help please? and if you could do explanations that would be great!!!

Mathematics
1 answer:
Luba_88 [7]2 years ago
4 0

Answer:

Step-by-step explanation:

8 times 6 = 48 (base times high = a rectangle). (A triangle takes half the space)

F. (6*8)/2 =24 square units

B. (2 * 3/2) / 2 = 3/2 = 1.5 square units

G. (4*3)/2 = 6 square units

H. (8/3 *2)/2 = 8/3 = 2.67 square units

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A triangle has side lengths of
Angelina_Jolie [31]

Answer:

3 is the right one

Step-by-step explanation:

Simple math you know

3 0
2 years ago
Find a polynomial with integer coefficients that satisfies the given conditions. R has degree 4 and zeros 3 − 3i and 2, with 2 a
dolphi86 [110]

Answer:

The required polynomial is P(x)=x^4-10x^3+46x^2-96x+72.

Step-by-step explanation:

If a polynomial has degree n and c_1,c_2,...,c_n are zeroes of the polynomial, then the polynomial is defined as

P(x)=a(x-c_1)(x-c_2)...(x-x_n)

It is given that the polynomial R has degree 4 and zeros 3 − 3i and 2. The multiplicity of zero 2 is 2.

According to complex conjugate theorem, if a+ib is zero of a polynomial, then its conjugate a-ib is also a zero of that polynomial.

Since 3-3i is zero, therefore 3+3i is also a zero.

Total zeroes of the polynomial are 4, i.e., 3-3i, 3_3i, 2,2. Let a=1, So, the required polynomial is

R(x)=(x-3+3i)(x-3-3i)(x-2)(x-2)

R(x)=((x-3)+3i)((x-3)-3i)(x-2)^2

R(x)=(x-3)^2-(3i)^2((x-3)-3i)(x-2)^2     [a^2-b^2=(a-b)(a+b)]

R(x)=(x^2-6x+9-9(i)^2((x-3)-3i)(x-2)^2

R(x)=(x^2-6x+18)(x^2-4x+4)                [i^2=-1]

R(x)=(x^2-6x+18)(x^2-4x+4)

R(x)=x^4-10x^3+46x^2-96x+72

Therefore the required polynomial is P(x)=x^4-10x^3+46x^2-96x+72.

3 0
3 years ago
Which equation should you use to solve for x?
oee [108]

Answer:

1st Option

Step-by-step explanation:

All angles in a triangle must add up to 180°.

Step 1: Set up equation

40° + 60° + 16x = 180°

Step 2: Rewrite

60° + 16x + 40° = 180°

8 0
3 years ago
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