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Vesnalui [34]
2 years ago
13

Examine this right triangle. A right triangle has a side length of 16 meters and hypotenuse of 20 meters. Which equation can be

used to find the missing leg in the triangle? a2 202 = 162 202 162 = a2 a2 162 =202 16 a2 = 20.
Mathematics
2 answers:
Sergeu [11.5K]2 years ago
3 0

The equation can be used to find the missing leg in the triangle 20^{2} = 16^{2} +a^{2}.

<h3>What is the right triangle?</h3>

A right-angle triangle is a triangle that has a side opposite to the right angle the largest side and is referred to as the hypotenuse.

It is given that a right triangle has a side length of 16 meters and a hypotenuse of 20 meters.

From a Pythagoras theorem

b^{2} = c^{2} +a^{2} \\20^{2} = 16^{2} +a^{2}\\20^{2}-16^{2} =a^{2}\\a^{2} = 20^{2}-16^{2} \\

Thus, the equation can be used to find the missing leg in the triangle 20^{2}-16^{2} =a^{2}.

Learn more about the right-angle triangle;

brainly.com/question/5474676

jok3333 [9.3K]2 years ago
3 0

Answer:

a2 + 162 =202

Step-by-step explanation:

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Answer:

Null hypothesis:\mu = 100  

Alternative hypothesis:\mu \neq 100  

t=\frac{98.375-100}{\frac{6.109}{\sqrt{12}}}=-0.921  

p_v =2*P(t_{11}  

Step-by-step explanation:

1) Data given and notation  

Data: 105.6, 90.9, 91.2, 96.9, 96.5, 91.3, 100.1, 105.0, 99.6, 107.7, 103.3, 92.4

We can calculate the sample mean and deviation for this data with the following formulas:

\bar X =\frac{\sum_{i=1}^n X_i}{n}

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s=0.6.109 represent the sample standard deviation  

n=12 sample size  

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\alpha represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

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We need to conduct a hypothesis in order to check if the mean is equal to 100pCL/L, the system of hypothesis are :  

Null hypothesis:\mu = 100  

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t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

3) Calculate the statistic  

We can replace in formula (1) the info given like this:  

t=\frac{98.375-100}{\frac{6.109}{\sqrt{12}}}=-0.921  

4) P-value  

First we need to find the degrees of freedom for the statistic given by:

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Since is a two sided test the p value would given by:  

p_v =2*P(t_{11}  

5) Conclusion  

If we compare the p value and the significance level assumed \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean is not significant different from 100 at 5% of significance.  

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