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Vesnalui [34]
2 years ago
13

Examine this right triangle. A right triangle has a side length of 16 meters and hypotenuse of 20 meters. Which equation can be

used to find the missing leg in the triangle? a2 202 = 162 202 162 = a2 a2 162 =202 16 a2 = 20.
Mathematics
2 answers:
Sergeu [11.5K]2 years ago
3 0

The equation can be used to find the missing leg in the triangle 20^{2} = 16^{2} +a^{2}.

<h3>What is the right triangle?</h3>

A right-angle triangle is a triangle that has a side opposite to the right angle the largest side and is referred to as the hypotenuse.

It is given that a right triangle has a side length of 16 meters and a hypotenuse of 20 meters.

From a Pythagoras theorem

b^{2} = c^{2} +a^{2} \\20^{2} = 16^{2} +a^{2}\\20^{2}-16^{2} =a^{2}\\a^{2} = 20^{2}-16^{2} \\

Thus, the equation can be used to find the missing leg in the triangle 20^{2}-16^{2} =a^{2}.

Learn more about the right-angle triangle;

brainly.com/question/5474676

jok3333 [9.3K]2 years ago
3 0

Answer:

a2 + 162 =202

Step-by-step explanation:

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What is the coefficient of the x^5y^5- term in the biomial expansion of (2x-3y)^10
jasenka [17]

<u>Answer:</u>

 The coefficient of x^{5} \times y^{5} \text { is }=\left(252 \times 2^{5} \times(-3)^{5}\right)=252 \times 32 \times 243=1959552

<u>Solution: </u>

The given expression is (2 x-3 y)^{10}

As per binomial theorem, we know,

(x+y)^{n}=\sum n C_{k} x^{n-k} y^{k}

Now here a = 2x, b = (- 3y) and n = 10 and k = 0,1,2,….10

Now x^{5}\times y^5 will be the 6 term where k =5

Now, \mathrm{T}_{6}=10 \mathrm{C}_{5} \times(2 \mathrm{x})^{(10-5)} \times(-3 \mathrm{y})^{5}=10 \mathrm{C}_{5} 2^{5} \times \mathrm{x}^{5} \times(-3)^{5} \times \mathrm{y}^{5}

So, the coefficient of x^{5} \times y^{5} \text { is }=10\left(5 \times 2^{5} \times(-3)^{5}\right.

10 \mathrm{C}_{5}=\frac{10 !}{5 ! \times(10-5) !}=\frac{10 !}{5 !+5 !}=\frac{10 \times 9 \times 8 \times 7 \times 6 \times 5 !}{5 ! \times 5 !}=\frac{10 \times 9 \times 8 \times 7 \times 6}{5 \times 4 \times 3 \times 2 \times 1}=\left(\frac{30240}{120}\right)=252

The coefficient of x^{5} \times y^{5} \text { is }=\left(252 \times 2^{5} \times(-3)^{5}\right)=252 \times 32 \times 243=1959552

6 0
3 years ago
Please help thank you
fiasKO [112]

Answer:

2 × n - 1 = x

Step-by-step explanation:

for example:

2(4) - 1 = 7

2(5) - 1 = x \\ 10 - 1 = x \\ x = 9

8 0
2 years ago
5 times as much as 16 diveded by 8
mixer [17]

The answer for this is 10

4 0
3 years ago
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Find c<br> <img src="https://tex.z-dn.net/?f=a%2Ba%3D10%5C%5Ca%2Bb%3D35%5C%5Cb-z%3D5%5C%5Cz%2Ba%2Bb%2Bc%3D%2010" id="TexFormula1
marin [14]
C=-50 a=5 b=30 z=25

25+5+30+(-50)=10
6 0
2 years ago
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Suppose you are standing in a parking lot near a building, and the winter air temperature is 0 degrees Celsius. At that temperat
Naily [24]

The building is 231.7 m far away.Distance can refer to a physical length or an estimate based on other factors in physics or common use.

<h3>What is distance?</h3>

Distance is a numerical representation of the space between two objects or locations. |AB| is a symbol for the distance between two points A and B.

Given data;

Speed of sound  = 331 meters per second

Time = 0.7 sec

The distance from the building is;

d=v×t

d=331 m/sec × 0.7 sec

d=231.7 m

Hence the building is 231.7 m far away.

To learn more about the distance refer to the link;

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#SPJ1

4 0
2 years ago
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