3 years ago

Can someone help geometry

Mathematics

1 answer:

Firlakuza [10]3 years ago

6 0

I hope that answer is AHS=JHL, AHJ=SHL

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What is the solution of the equation?<br>-5=q+2

jeyben [28]

Step-by-step explanation:

-5=q+2

-5+2=q

q= -3

hope it helps.

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3 years ago

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Help it's due tomorrow!!!!

zepelin [54]

8a^2 + 3a^2

11a^2

since both have a^2 you only have to add the coefficients

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3 years ago

Find the cross product (7,-4,5) x (6,2,9). is the resulting vector perpendicular to the given vectors ?

Nutka1998 [239]

Answer:

Step-by-step explanation:

On edge

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4 years ago

Help ur homie out pls

MrMuchimi

I'm still doing the rest but number 1 is D

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3 years ago

A machine has four components, A, B, C, and D, set up in such a manner that all four parts must work for the machine to work pro

olchik [2.2K]

Answer:

0.756

Step-by-step explanation:

It is given that a machine has four components, A, B, C, and D.

$P(A)=P(B)=0.93, P(C)=0.95,P(D)=0.92$

If these components set up in such a manner that all four parts must work for the machine to work properly.

We need to find the probability that the machine works properly. It means we have to find the value of $P(A\cap B\cap C\cap D)$ .

If two events X and Y are independent, then

$P(X\cap Y)=P(X)\times P(Y)$

Assume the probability of one part working does not depend on the functionality of any of the other parts.

$P(A\cap B\cap C\cap D)=P(A)\times P(B)\times P(C)\times P(D)$

Substitute the given values.

$P(A\cap B\cap C\cap D)=0.93\times 0.93\times 0.95\times 0.92$

$P(A\cap B\cap C\cap D)=0.7559226$

$P(A\cap B\cap C\cap D)\approx 0.756$

Therefore, the probability that the machine works properly is 0.756.

7 0

3 years ago