I = PRT
21 = 200 * 0.035 * T
21 = 7T
3 years = T
Answer:
Neighborhood Q appears to have a bigger family size
Step-by-step explanation:
Mean = the sum of all data values divided by the total number of data values
Number of families in Neighborhood Q = 9
Mean family size of Neighborhood Q:
= (2 + 5 + 4 + 3 + 2 + 5 + 3 + 6 + 5) ÷ 9
= 35 ÷ 9
= 3.888888...
Number of families in Neighborhood S = 9
Mean family size of Neighborhood S:
= (2 + 3 + 2 + 3 + 7 + 2 + 3 + 3 + 2) ÷ 9
= 27 ÷ 9
= 3
The mean family size of Neighborhood Q is 3.88.. and the mean family size of Neighborhood S is 3. Therefore, Neighborhood Q appears to have a bigger family size as it's average family size is bigger than that of Neighborhood S.
Twice a number (2x) decreased by 7 (- 7).
2x - 7
Two times a specfic number (x) subtracted by 7.
Step-by-step explanation:
1. What the GCF
the GCF is 4
4(x + 8)
2. divide by 4
4(x+8) is the solution
64x2.40 = 153.6
64x1.90 = 121.6
add 153.6 to 121.6
275.2
