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zaharov [31]
3 years ago
10

Which postulate proves these two triangles are congruent?

Mathematics
1 answer:
Korvikt [17]3 years ago
6 0

Answer:

C. HL

Step-by-step explanation:

Since both triangles have a congruent hypotenuse (they share the same hypotenuse) and both have a 90° angle, with a congruent leg, then the postulate that proves these two triangles are congruent, would be the HL (hypotenuse leg) postulate.

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Which property is shown? (mn)5 = m5n5
sineoko [7]
In this item, we are asked to identify which among the given choices is a property that is being shown by the equation,
 
                         (mn)⁵ = m⁵n⁵

It can be observed that m and n are multiplied to each other, inside the parentheses for the expression written on the left side of the equation. Also in the right hand side of the equation, 5 which is the power, is distributed to the elements m and n. 

The property that is being depicted in this number is the power of a product property. Thus, the answer to this item is letter B. 
7 0
4 years ago
. The product of two integers is -84. One of them is 4, find the other integer.​
Marina CMI [18]

Answer:

<h2><u>Answer </u><u>:</u><u>-</u></h2>

Product of two integers = - 84

One integer = 4

Other integer = x

4 \times x =  - 84 \\ 4x =  - 84 \\ x =  \frac{ - 84}{4}  \\ x =  - 21

<u>⎆ The value of the other integer is - 21</u>

3 0
3 years ago
HELP ASAP <br> H(x)=-6x+8<br> G(x)=10-2x<br><br> H(G(x))
galben [10]

<u>Answer:</u>

H(G(x)) = 12x - 52

<u>Step-by-step explanation:</u>

We are given the following two functions:

H ( x ) = - 6 x + 8

G ( x ) = 1 0 - 2 x

And we are to find the value of H(G(x)).

For that, we will apply the function of H on the function of G.

H(G(x))=H(10-2x)

H ( G ( x ) ) = - 6 ( 1 0 - 2 x ) + 8

H(G(x))=-60+12x+8

H(G(x)) = 12x - 52

7 0
3 years ago
Please help, This is confusing. I'll mark brainiest
Sliva [168]

Answer: a.

Look at the tables closely, many of them are either trick questions or flat out wrong.

7 0
3 years ago
If 3t − 7 = 5t , then 6t = how do you solve this
Alik [6]
3t-7=5t \ \ \ |\hbox{subtract 3t} \\ -7=5t-3t \\ -7=2t \ \ \ |\hbox{multiply by 3} \\ \boxed{6t=-21}}
4 0
3 years ago
Read 2 more answers
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