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3 years ago

HELP ASAP H(x)=-6x+8 G(x)=10-2x H(G(x))

Mathematics

1 answer:

galben [10]3 years ago

7 0

Answer:

H(G(x)) = 12x - 52

Step-by-step explanation:

We are given the following two functions:

$H ( x ) = - 6 x + 8$

$G ( x ) = 1 0 - 2 x$

And we are to find the value of H(G(x)).

For that, we will apply the function of H on the function of G.

$H(G(x))=H(10-2x)$

$H ( G ( x ) ) = - 6 ( 1 0 - 2 x ) + 8$

$H(G(x))=-60+12x+8$

H(G(x)) = 12x - 52

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the library is 0.9 miles from school. the museum is 0.6 times as far from the school as the library. how far is the museum from

LiRa [457]

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3 years ago

Read 2 more answers

Use the Distributive Property to rewrite the expression. 9(y + 4)

Ulleksa [173]

Answer:

Answer would be 9y+36

Step-by-step explanation:

Because if you distribute the 9 inside the parenthesis, you'd get

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Hope my answer was helpful to you!

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4 years ago

Write the equation of a parabola having the vertex (1, −2) and containing the point (3, 6) in vertex form. Then, rewrite the equ

In-s [12.5K]

PART A

The equation of the parabola in vertex form is given by the formula,

$y - k = a {(x - h)}^{2}$

where

$(h,k)=(1,-2)$

is the vertex of the parabola.

We substitute these values to obtain,

$y + 2 = a {(x - 1)}^{2}$

The point, (3,6) lies on the parabola.

It must therefore satisfy its equation.

$6 + 2 = a {(3 - 1)}^{2}$

$8= a {(2)}^{2}$

$8=4a$

$a = 2$
Hence the equation of the parabola in vertex form is

$y + 2 = 2 {(x - 1)}^{2}$

PART B

To obtain the equation of the parabola in standard form, we expand the vertex form of the equation.

$y + 2 = 2{(x - 1)}^{2}$

This implies that

$y + 2 = 2(x - 1)(x - 1)$

We expand to obtain,

$y + 2 = 2( {x}^{2} - 2x + 1)$

This will give us,

$y + 2 = 2 {x}^{2} - 4x + 2$

$y = {x}^{2} - 4x$

This equation is now in the form,

$y = a {x}^{2} + bx + c$
where

$a=1,b=-4,c=0$

This is the standard form

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3 years ago

100 POINTS!! PLEASE HELP IM REALLY CONFUSED

11111nata11111 [884]

Answer:

<A=½(arcJL)=½(70+120)=35+60=95°