Answer:
If we define the random variable X ="time spend by the students doign homework"
And we want to tes t is students spend more than 1 hour doing homework per night, on average (alternative hypothesis), so then the system of hypothesis for this case are:
Null hypothesis: 
Alternative hypothesis: 
And they wnat to use a sample size of n = 100 and a significance level of 0.05
Step-by-step explanation:
Previous concepts
A hypothesis is defined as "a speculation or theory based on insufficient evidence that lends itself to further testing and experimentation. With further testing, a hypothesis can usually be proven true or false".
The null hypothesis is defined as "a hypothesis that says there is no statistical significance between the two variables in the hypothesis. It is the hypothesis that the researcher is trying to disprove".
The alternative hypothesis is "just the inverse, or opposite, of the null hypothesis. It is the hypothesis that researcher is trying to prove".
Solution to the problem
If we define the random variable X ="time spend by the students doign homework"
And we want to tes t is students spend more than 1 hour doing homework per night, on average (alternative hypothesis), so then the system of hypothesis for this case are:
Null hypothesis: 
Alternative hypothesis: 
And they wnat to use a sample size of n = 100 and a significance level of 0.05

<u>Ratio of two angles are 6:13.</u>
So, let the one angle be
and another be 
As we know that,
Sum of all interior angles of a quadrilateral = 
So let's sum up the given angles,






Hence, 
So, First angle

Second angle

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Hope it helps you:)
The store clerk gave the customer:
Gas. . . . . . . . . 17.01
$5 ticket . . . . . . 5
$3 ticket . . . . . . 3
2 x $1 ticket . . . 2
Total. . . . . . . $27.01
The customer gave the store clerk:
$5 ticket . . . 5
$2 ticket . . . 2
cash. . . . . 100
Total. . . . $107
The store clerk owes the customer ($107 - $27.01) = $ 79.99 .
In general if multiplying, move decimal to RIGHT by whatever the exponent is.
In this example 10^1, the exponent = 1
9.4 with decimal moved 1 place to right = 94