Answer:
i dont under stand sorry i cant help sorry
Answer:
e
Step-by-step explanation:
ddd
The probability that the transistor will last between 12 and 24 weeks is 0.424
X= lifetime of the transistor in weeks E(X)= 24 weeks
O,= 12 weeks
The anticipated value, variance, and distribution of the random variable X were all provided to us. Finding the parameters alpha and beta is necessary before we can discover the solutions to the difficulties.
X~gamma(
)
E(X)=
=
=6 weeks
V(x)=
=24/6= 4
Now we can find the solutions:
The excel formula used to create Figure one is as follows:
=gammadist(X,
,
, False)
P(
)
P(
)
P(
)
P= 0.424
Therefore, probability that the transistor will last between 12 and 24 weeks is 0.424
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Answer:
y=a(x-p)(x-q)
y=a(x+2+√2)(x+2-√2)
passing through point (-1,1)
substitute
1=a(-1+2+√2)(-1+2-√2)
1=a(1+√2)(1-√2)
1=a(1-2)
1=a(-1)
a=1/(-1)
a=-1
y=-(x+[2+√2])(x+[2-√2])
y=-(x2+4x+2)
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The equation represented by Ms. Wilson's model is n² + 13n + 40 = (n + 8)(n + 5)
<h3>How to determine the equation of the model?</h3>
The partially completed model is given as:
| n
| n²
5 | 5n | 40
By dividing the rows and columns, the complete model is:
| n | 8
n | n² | 8n
5 | 5n | 40
Add the cells, and multiply the leading row and columns
n² + 8n + 5n + 40 = (n + 8)(n + 5)
This gives
n² + 13n + 40 = (n + 8)(n + 5)
Hence, the equation represented by Ms. Wilson's model is n² + 13n + 40 = (n + 8)(n + 5)
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