Hello from MrBillDoesMath!
Answer: C)
Discussion:
To solve x^2 = 36/81 take the square root of both sides.
x = square root of (36/81)
As 36 = 6*6 and 81 = 9*9,
x = square root of (6*6)/ (9.9) or 6/9
But 6 and 9 share the common factor "3" so
x = 6/9 = (2*3)/(3*3) = 2/3
The last equality was gotten by cancelling the common factor 3.
Regards, MrB
If s(t) = 3 sin(2 (t - π/6)) + 5, then the derivative is
s'(t) = 3 cos(2 (t - π/6)) • 2 = 6 cos(2 (t - π/6))
The critical points of s(t) occur at the values of t where s'(t) is zero or undefined. s'(t) is continuous everywhere, so we only need worry about the first case. We have
6 cos(2 (t - π/6)) = 0
cos(2t - π/3) = 0
2t - π/3 = arccos(0) + nπ
(where n is any integer)
2t - π/3 = π/2 + nπ
2t = 5π/6 + nπ
t = 5π/12 + nπ/2
If you're only looking for t in the interval [0,2π), then you have four critical points at t = 7π/12, t = 11π/12, t = 17π/12, and t = 23π/12.
15: Approximately it is 46.6%.
16: 7%(100%-65%-18%-10%)
Answer:
Probability that their mean credit card balance is less than $2500 is 0.0073.
Step-by-step explanation:
We are given that a bank auditor claims that credit card balances are normally distributed, with a mean of $3570 and a standard deviation of $980.
You randomly select 5 credit card holders.
Let<em> </em>
<em> = </em><u><em>sample mean credit card balance</em></u>
The z score probability distribution for sample mean is given by;
Z =
~ N(0,1)
where,
= population mean credit card balance = $3570
= standard deviation = $980
n = sample of credit card holders = 5
Now, the probability that their mean credit card balance is less than $2500 is given by = P(
<em> </em>< $2500)
P(
<em> </em>< $2500) = P(
<
) = P(Z < -2.44) = 1 - P(Z
2.44)
= 1 - 0.9927 = 0.0073
The above probability is calculated by looking at the value of x = 2.44 in the z table which has an area of 0.9927.
Therefore, probability that their mean credit card balance is less than $2500 is 0.0073.
Answer:
C * 9 = P
9C = P
Step-by-step explanation:
Each cake is 9 pieces
Cakes times 9 equals pieces
c * 9 = P