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vampirchik [111]
3 years ago
9

(5•2+20/2)+(10•2/2+5)

Mathematics
1 answer:
Olin [163]3 years ago
8 0

Answer:

35

Step-by-step explanation:

Parenthesis

Exponent

Multiply

Divide

Add

Subtract

<em>Do parenthesis, and then remove.</em>

<em>5*2+20/2+10*2/2+5</em>

<em>Multiply and divide the numbers from left to right.</em>

<em>5*2=10</em>

<em>20/2=10</em>

<em>10*2/2=10</em>

<em>10+10+10+5</em>

<em>Add the numbers from left to right.</em>

<em>10+10+10+5=35</em>

<em>35 is the correct answer.</em>

<em>I hope this helps you, and have a wonderful day!</em>

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Step-by-step explanation:

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2 years ago
Wats is the answer to this question
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Simplify the radical by breaking the radicand up into a product of known factors in other words take the cube root of 27 then for the exponent 9 you divide by 3 get

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3 years ago
A soccer ball is kicked in the air and follow the path h(x)=2x2+1x+6, where x is the time in seconds and h is the height of the
denis-greek [22]

Answer:

You can either factor or use quadratic formula to find where h(x)=0

Step-by-step explanation:

Remember that the ball is on the ground when h(x)=0 since that is the height. There will be two zeros,  one is a negative number so would be before you kicked the ball, the other one will be when the ball comes back down.

4 0
3 years ago
Arrange the geometric series from least to greatest based on the value of their sums.
son4ous [18]

Answer:

80 < 93 < 121 < 127

Step-by-step explanation:

For a geometric series,

\sum_{t=1}^{n}a(r)^{t-1}

Formula to be used,

Sum of t terms of a geometric series = \frac{a(r^t-1)}{r-1}

Here t = number of terms

a = first term

r = common ratio

1). \sum_{t=1}^{5}3(2)^{t-1}

   First term of this series 'a' = 3

   Common ratio 'r' = 2

   Number of terms 't' = 5

   Therefore, sum of 5 terms of the series = \frac{3(2^5-1)}{(2-1)}

                                                                      = 93

2). \sum_{t=1}^{7}(2)^{t-1}

   First term 'a' = 1

   Common ratio 'r' = 2

   Number of terms 't' = 7

   Sum of 7 terms of this series = \frac{1(2^7-1)}{(2-1)}

                                                    = 127

3). \sum_{t=1}^{5}(3)^{t-1}

    First term 'a' = 1

    Common ratio 'r' = 3

    Number of terms 't' = 5

   Therefore, sum of 5 terms = \frac{1(3^5-1)}{3-1}

                                                 = 121

4). \sum_{t=1}^{4}2(3)^{t-1}

    First term 'a' = 2

    Common ratio 'r' = 3

    Number of terms 't' = 4

    Therefore, sum of 4 terms of the series = \frac{2(3^4-1)}{3-1}

                                                                       = 80

    80 < 93 < 121 < 127 will be the answer.

4 0
3 years ago
Read 2 more answers
The number of coins on the third day will be 2x2x2. Can you write
ZanzabumX [31]

Answer:

2^{3}

Step-by-step explanation:

2*2*2 = 2^{3}

5 0
3 years ago
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