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3 years ago

(5•2+20/2)+(10•2/2+5)

Mathematics

1 answer:

Olin [163]3 years ago

8 0

Answer:

Step-by-step explanation:

Parenthesis

Exponent

Multiply

Divide

Add

Subtract

Do parenthesis, and then remove.

5*2+20/2+10*2/2+5

Multiply and divide the numbers from left to right.

5*2=10

20/2=10

10*2/2=10

10+10+10+5

Add the numbers from left to right.

10+10+10+5=35

35 is the correct answer.

I hope this helps you, and have a wonderful day!

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The sum of two integers is 33. The larger is 6 more than twice the smaller. Find the two

grandymaker [24]

Answer:

24 and 9

Step-by-step explanation:

Hi there!

Let x be equal to the larger integer.

Let y be equal to the smaller integer.

1) Construct equations

$x+y=33$ (The sum of two integers is 33)
$x=6+2y$ (The larger is 6 more than twice the smaller)

2) Solve for one of the integer

Isolate x in the first equation

$x+y=33\\x=33-y$

Plug the first equation into the second

$33-y=6+2y$

Combine like terms

$33-6=2y+y\\27=3y\\9=y$

Therefore, the smaller integer is 9.

3) Solve for the other integer

$x+y=33$

Plug in y (9)

$x+9=33\\x=33-9\\x=24$

Therefore, the larger integer is 24.

I hope this helps!

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