PLEASE HELP I WILL GIVE BRAINLIEST TO RIGHT ANSWER

1 answer:

4 0

1: 19 (4x+25=6x -13, solve for x, 25+13=6x-13, 38=2x, x=19, 4(19)+25=101 6(19)-13+101)

2: 23 (3x-8=2x+15)

3: Madison has $59 and Saul has $31 (together they have $90 so divided by 2 and you get 45, Madison has 6 dollars more so subtract 6 from Saul and ad 6 to Madison, make sure that when you ad them you get $90)

4 : 5 weeks ($3 each week, so you multiply 3x5 and get 15. 15+57=72 but the problem says more then so maybe it’s 6 weeks cause that’s $75)

5: 10 weeks (he has 1,800 and needs 2,150, subtract 1,800 from 2,150 for how much he needs. You get 350. He needs that and he makes 35 a week so that would be 350 divided by 35, which is 10)

6:20 miles (it’s 2.25 for that’s first mile. He spent 6.05 so subtract 2.25 from 6.05 and you get 3.80, 3.80 divided by 0.20 is 19, then you need to add that first mile and it’s 20)

7: 6 figures in a complete set (Charlie starts out with 2 and Patrick starts out with 20 individual figures. Charlie has 6 sets and Patrick has 3, i multiplied the number of sets they had by 6 then added their individual figures until they numbers matched up)

8: an orange has 45 calories and an apple has 75 calories (5x-150=3x, 5x-3x= -2x, -2x divided by -150 = 75, 75-30 is 45. 75 is the apple and because it’s 30 more you subtract 30 for orange)

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Use the Polygon tool to draw the image of the given quadrilateral under a dilation with a scale

Nataly [62]

Answer: See the picture attached.

Step-by-step explanation:

A Dilation is defined as a transformation in which the image and the pre-image have the same shape, but their sizes are different.

When the scale factor is greater than 1, the image obtained after the dilation is greater than the pre-image and it is an "Enlargement".

When the scale factor is is between 0 and 1, the image obtained after the dilation is smaller than the pre-image and it is an "Reduction".

In this case we know that the scale factor is:

$scale\ factor=\frac{2}{3}$

Since:

$0$

It is a Reduction.

You can identify that the vertices of the quadritaleral are:

$(-3,0),(-9,-3),(-6,-9),(3,-6)$

So you need to multiply the coordinates of eac vertex by $\frac{2}{3}$ in order to get the coordinates of the image.

Then, you get:

$(\frac{(-3)(2)}{3},0*\frac{2}{3})=(-2,0)\\\\(\frac{(-9)(2)}{3}),\frac{(-3)(2)}{3})=(-6,-2)\\\\(\frac{(-6)(2)}{3},\frac{(-9)(2)}{3})=(-4,-6)\\\\(3*\frac{2}{3},\frac{(-6)(2)}{3})=(2,-4)$