Yes you do and what grade are you in and do you need help answering these questions
Answer:
<em>dear </em><em>option</em><em> </em><em>C </em><em>(</em><em>2</em><em>,</em><em>4</em><em>,</em><em>6</em><em>)</em><em> </em><em>is </em><em>correct</em><em> </em><em>for </em><em>this </em><em>question</em>
<em>as,</em>
<em>domain </em><em>=</em><em> </em><em>is </em><em>all </em><em>set </em><em>of </em><em>input </em><em>values</em>
<em>and</em>
<em>range </em><em>=</em><em> </em><em>is </em><em>all </em><em>set </em><em>of </em><em>output </em><em>value</em>
<em><u>hope </u></em><em><u>this </u></em><em><u>answer </u></em><em><u>helps </u></em><em><u>u </u></em><em><u>dear!</u></em>
Answer:
Option D is correct.
Explanation:
Commutative Property of Multiplication define that two numbers can be multiplied in any order.
i.e
Distributive property of multiplication states that when a number is multiplied by the sum of two numbers i.e, the first number can be distributed to both of those numbers and multiplied by each of them separately.

Associative property of multiplication states that multiplication allows us to group factors in different ways to get the same product.
Given:
A = 
B = 
C = 
then;

Using Commutative property of Multiplication we can write
then we have;

Using Distributive property of multiplication;

by using associative property of multiplication ,

Therefore, the reasons for A , B and C in this proof are;
A.commutative property of multiplication
B. distributive property
C. associative property of multiplication
Hi!
Let's first expand the cotangent of theta.
You'll probably know that tangent will be "y/x", or
, and cotangent is the reciprocal of this, meaning that it is "x/y" or
.
That means that we are now given this equation.

That'll multiply to:

We'll want a common denominator to add by multiplying
to both top and bottom of the second term:


Pythagorean Identity states that
, so substitute that in:

Which simplifies to:

Hope this helps!