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Margarita [4]
3 years ago
8

The difference between six times a number and 7 is equal to five times the sum of the number and 4. Find the number.

Mathematics
1 answer:
pochemuha3 years ago
8 0
The difference (subtraction) of 6 times a number (x represents number) and 7. This gives us 6x-7. That is equal to five times (multiplication) the sum (addition) of the number, x, and 4. This gives you = 5(x+4) and combined gives us B, 6x-7=5(x+4).
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Solve the following inequalities:<br><br> <img src="https://tex.z-dn.net/?f=-%28x%2B2%29%5E%7B2%7D%20%28x-3%29%28x%2B3%29%28x-4%
Salsk061 [2.6K]
<h2>Answer:</h2>

\boxed{(-\infty,-3] \ U \ [3,4] \ U \ \{-2\}}

<h2>Step-by-step explanation:</h2>

To solve this problem we need to use the Test Intervals for Polynomial. The following steps helps us to determine the intervals on which the values of a polynomial are entirely  negative or entirely positive.

1. Find all real zeros of the polynomial arranging them in increasing order from smallest to largest. We call these zeros the critical numbers of the polynomial.

Before we start applying this steps, let's multiply the entire inequality by -1 changing the direction of the inequality, so the result is:

(x+2)^2(x-3)(x+3)(x-4)\leq 0

So the real zeros are:

x_{1}=-3 \\ \\ x_{2}=-2 \\ \\ x_{3}=3 \\ \\ x_{4}=4

2. Use the real zeros of the polynomial to determine its test intervals.

(-\infty,-3) \\ \\ (-3,-2) \\ \\ (-2,3) \\ \\ (3,4)

3. Take one representative x-value in each test interval, then evaluate the polynomial at this value. If the value of the polynomial is negative, the polynomial will have negative values for every x-value in the interval. If the value of the polynomial is positive, the polynomial will have positive values for every x-value in the interval.

<u>Polynomial values</u>

___________________

(-\infty,-3): \ (-4+2)^2(-4-3)(-4+3)(-4-4)=-224 \ NEGATIVE \\ \\(-3,-2): \ (-2.5+2)^2(-2.5-3)(-2.5+3)(-2.5-4)=4.46 \ POSITIVE \\ \\ (-2,3): \ (-1+2)^2(-1-3)(-1+3)(-1-4)=40 \ POSITIVE \\ \\ (3,4): \ (3.5+2)^2(3.5-3)(3.5+3)(3.5-4)=-49.15 \ NEGATIVE \\ \\ (4,\infty): \ (5+2)^2(5-3)(5+3)(5-4)=784 \ POSITIVE

___________________

At x = -3, x = 3, and x = 4 we use brackets because the inequality includes the value at which the polynomial equals zero.

Finally, if you set x=-2:

(x+2)^2(x-3)(x+3)(x-4)\leq 0 \\ \\ (-2+2)^2(-2-3)(-2+3)(-2-4)\leq 0 \\ \\ 0\leq 0

So x=-2 is also a solution to the system. Finally, the solution is:

\boxed{(-\infty,-3] \ U \ [3,4] \ U \ \{-2\}}

8 0
3 years ago
) What is the distance between this pair of points?<br> (-5, 2) and (-5, 6)
Leni [432]

Answer:

d=4

Step-by-step explanation:

Distance Formula: d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Simply plug in the 2 coordinates into the distance formula to find distance <em>d</em>:

d=\sqrt{(-5-(-5))^2+(6-2)^2}

d=\sqrt{(-5+5)^2+(4)^2}

d=\sqrt{(0)^2+16}

d=\sqrt{0+16}

d=\sqrt{16}

d=4

5 0
4 years ago
Solve the equation.<br><br><br> d – 267 = 145
Rus_ich [418]

Answer: d= 412

i did 267+145 and that was 412 then i did 212-267 and got 145

7 0
3 years ago
Read 2 more answers
HELP PLS!! <br> Write the inequality shown by the graph
larisa [96]

Answer: y>-2/6+2

Step-by-step explanation:

We know it's greater then so we just need to find the line. Let's look at the Slope, since 0,2 is greater than -6,4 we start there. The y of 0,2 is 2 so we subtract 4 from 2 which is -2 and now we subtract -6 from 0 which is 6 so now we have -2/6 and the intercept is 2 so we now have y=mx+b which is the line in black: y=-2/6+2. But it is greater than so its y>-2/6+2

6 0
3 years ago
Someone, please help me
zaharov [31]

Answer:

I dont know

Step-by-step explanation:

6 0
3 years ago
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