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DedPeter [7]
3 years ago
8

Sum of two numbers = 16 Difference of the numbers = 6 Find the numbers. What if their product?

Mathematics
1 answer:
Oksana_A [137]3 years ago
4 0
Numbers x and y
sum of the two = 16: x + y = 16
difference of the two = x - y = 6
solve one of the equations for one variable:
I'm going to solve x - y = 6, for x
(x - y) + y = 6 + y, x = y + 6
Now plug that into the other equation:
x + y = 16, (y+6) + y = 16
(y+y) + 6 = 16
2y + 6 - 6 = 16 - 6
2y = 10
2y/2 = 10/2
y = 5
Now plug that solved y-value into either original equation: x - y = 6, x - 5 = 6
(x-5) + 5 = 6 + 5
x = 11
So now we have their values: x=11, y=5
But always double-check what the question asked... What is their product??
So x*y = 11*5 = 55
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1.3x - 10= 0.8x - 8<br> solve for x
OverLord2011 [107]

Answer:

x = 4

Step-by-step explanation:

1.3x - 10 = 0.8x - 8

Add 10 to both sides.

1.3x = 0.8x + 2

Subtract 0.8x from both sides.

0.5x = 2

Divide by 0.5.

x = 4.

Proof:

1.3x - 10 = 0.8x - 8

1.3(4) - 10 = 0.8(4) - 8

5.2 - 10 = 3.2 - 8

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3 years ago
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mariarad [96]

Answer:

The answer is \frac{7\pi }{12}^{c}=105^{0}

Step-by-step explanation:

The expression is

\frac{7\pi }{12}^{c}\\= \frac{7\pi }{12}*\frac{180}{\pi }^{0} \,;[1^{c}=\frac{180}{\pi}^{0}]\\=7*15\\=105^{0}

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8 0
3 years ago
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irina1246 [14]
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What is 18 as a product of its prime factors
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3 0
3 years ago
a group friends ordered 3 burgers and 3 medium fries for a total of 20.25 .Another group of friends ordered 5 burgers and 8 medi
matrenka [14]
Answer: a burger is $5.25, fries are $1.50

b = burger, f = fries
3b + 3f = 20.25
5b + 8f = 38.25

First, solve for b in terms of f
3b = 20.25 - 3f
b = 6.75 -f

Then substitute that for b in the other equation to solve and get a numerical value for f.

5(6.75 -f) + 8f = 38.25
33.75 -5f +8f = 38.25
33.75 + 3f = 38.25
3f = 4.5
f = 1.5

Now substitute that in to get a numerical value for b
b = 6.75 - 1.5
b = 5.25

Checking the math:
3b + 3f = 20.25
3(5.25) + 3(1.5) = 15.75 + 4.5 = 20.25
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3 years ago
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