<span>Consider a angle â BAC and the point D on its defector
Assume that DB is perpendicular to AB and DC is perpendicular to AC.
Lets prove DB and DC are congruent (that is point D is equidistant from sides of an angle â BAC
Proof
Consider triangles ΔADB and ΔADC
Both are right angle, â ABD= â ACD=90 degree
They have congruent acute angle â BAD and â CAD( since AD is angle bisector)
They share hypotenuse AD
therefore these right angle are congruent by two angle and sides and, therefore, their sides DB and DC are congruent too, as luing across congruent angles</span>
Answer:
$10
Step-by-step explanation:
The question made is How much did I have? This question is about the amount of money that you had before receiving the money from your mom, dad and aunt and uncle. This means that the answer is the $3 you had plus the other $7 you said you had. So, $3+$7=$10. You had $10.
Answer:
x=19, y=-5
Step-by-step explanation:
Add the equations in order to solve for the first variable. Plug this value into the other equations in order to solve for the remaining variables.
Point Form:
(19, -5)
Equation Form:
x=19, y=-5
Hope this helps.
Answer:
( negative infinity, infinity)
Step-by-step explanation:
Answer:
The interest is equal to \$13$13
we know that
The compound interest formula is equal to
A=P(1+\frac{r}{n})^{nt}A=P(1+
n
r
)
nt
where
A is the Final Investment Value
P is the Principal amount of money to be invested
r is the rate of interest in decimal
t is Number of Time Periods
n is the number of times interest is compounded per year
in this problem we have
\begin{gathered}t=3\ years\\ P=\$80\\ r=0.05\\n=1\end{gathered}
t=3 years
P=$80
r=0.05
n=1
substitute in the formula above
A=\$80(1+\frac{0.05}{1})^{3}=\$92.61A=$80(1+
1
0.05
)
3
=$92.61
Find the interest
I=A-P=\$92.61-\$80=\$12.61I=A−P=$92.61−$80=$12.61
Round to the nearest whole dollar
\$12.61=\$13$12.61=$13
