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PSYCHO15rus [73]
4 years ago
7

Which polynomial is equivalent to (2h − 3k)(h + 5k)?

Mathematics
1 answer:
Luba_88 [7]4 years ago
3 0

Answer:

2h^{2}  + 7hk - 15k^{2}

Step-by-step explanation:

Distribute (2h − 3k)(h + 5k).

2h^2 + 10hk - 3hk - 15k^2

2h^2 + 7hk 15k^2

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Answer:5

Step-by-step explanation:

2 +3=5

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Which graph best represents the equation 5x + y = 4? A. B. C. D.
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Suppose that prices of a certain model of a new home are normally distributed with a mean of $150,000. Use the 68-95-99.7 rule t
levacccp [35]

Answer:

68% of buyers paid between $147,700 and $152,300.

Step-by-step explanation:

We are given that prices of a certain model of a new home are normally distributed with a mean of $150,000.

Use the 68-95-99.7 rule to find the percentage of buyers who paid between $147,700 and $152,300 if the standard deviation is $2300.

<u><em>Let X = prices of a certain model of a new home</em></u>

SO, X ~ Normal(\mu=150,000 ,\sigma=2,300)

The z score probability distribution for normal distribution is given by;

                             Z  =  \frac{X-\mu}{\sigma}  ~ N(0,1)

where, \mu = population mean price = $150,000

            \sigma = standard deviation = $2,300

<u>Now, according to 68-95-99.7 rule;</u>

Around 68% of the values in a normal distribution lies between \mu-\sigma and \mu-\sigma.

Around 95% of the values occur between \mu-2\sigma and \mu+2\sigma .

Around 99.7% of the values occur between \mu-3\sigma and \mu+3\sigma.

So, firstly we will find the z scores for both the values given;

         Z  =  \frac{X-\mu}{\sigma}  =  \frac{147,700-150,000}{2,300}  = -1

         Z  =  \frac{X-\mu}{\sigma}  =  \frac{152,300-150,000}{2,300}  = 1

This indicates that we are in the category of between \mu-\sigma and \mu-\sigma.

SO, this represents that percentage of buyers who paid between $147,700 and $152,300 is 68%.

7 0
4 years ago
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egoroff_w [7]

Answer:

Solution given:

r=3km

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is a required answer

6 0
3 years ago
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saul85 [17]

Answer:

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