To solve for the values in the variable knowing that the sum of all angles in a triangle add to 180 degrees. Simply use this fact to determine the value of z.
Z = 180 - 115 = 165
Then to solve for x, do the same thing. Add up 51 and 45 and subtract the sum by the 165 degrees.
To solve for y, simply knowing the angle that is present for both 70 and the unknown is 180. Subtract 180 from y.
To actually solve for y add up the value for x and 51 and subtract that amount by 180 degrees.
I will assume you mistyped this question. For y = -1/16x^2 + 4x + 3, the answers to this question are
a) 3 feet
b) 67 feet
c) 64.741 feet
For a) we note that at x = 0, that is the instant where the ball leaves the hand. y(0) = 0.
For b), we find the vertex of y = -1/16x^2 + 4x + 3
y = -1/16x^2 + 4x + 3
y = -1/16(x^2 - 64x) + 3
y = -1/16(x^2 - 64x + 1024 - 1024) + 3
y = -1/16((x-32)^2 - 1024) + 3
y = -1/16(x-32)^2 + 64 + 3
y = -1/16(x-32)^2 + 67
The vertex is at (32,67) so 67 is the maximum height.
For c), we find the x-intercepts with the quadratic formula on
y = -1/16x^2 + 4x + 3=0:
x = [ -b ± √b^2 - 4ac ] / (2a)<span>
x = [ -4 ± √4^2 - 4(-1/16)(3) ] / (2(-1/16))
x = -0.741, 64.741
Only the positive solution, so 64.741 feet </span>
$520
First, you multiply 26 by 4.
Then you multiply the product (104) by 5.
Answer:
The generalisation she can make from her work is that the other two angles of the quadrilateral are supplementary i.e their sum is 180°
Step-by-step explanation:
We are given the following from what she knows
m∠3=2⋅m∠1... 1
m∠2=2⋅m∠4 ... 2
m∠2+m∠3=360 ... 3
From what is given, we can substitute equation 1 and 2 into equation 3 as shown:
From 3:
m∠2+m∠3=360
Substituting 1 and 2 we will have:
2⋅m∠4 + 2⋅m∠1 = 360
Factor out 2 from the left hand side of the equation
2(m∠4+m∠1) = 360
Divide both sides by 2
2(m∠4+m∠1)/2 = 360/2
m∠4+m∠1 = 180°
Since the sum of two supplementary angles is 180°, hence the generalisation she can make from her work is that the other two angles of the quadrilateral are supplementary i.e their sum is 180°