Taking the square root of both sides gives two possible cases,
or
Recall that
If 
and 
, we have
so in the equations above, we can write
Then in the first case,
(where 
is any integer)
and in the second,
Then the solutions that fall in the interval 
are
The numbers aren't accurate, they dont add up
Answer:
Step-by-step explanation:a = m + (p-1)*d
b = m + (q-1)*d
c = m + (r-1)*d
p(b-c) = p*(q-r)*d
q(c-a) = q*(r-p)*d
r(a-b) = r*(p-q)*d
p(b-c)+q(c-a)+r(a-b)
= p*(q-r)*d + q*(r-p)*d +r*(p-q)*d
= (pq-pr+qr-pq+rp-qr)*d
= 0*d = 0
So i prove p(b-c)+q(c-a)+r(a-b)=0 hope this is helpfull
The correct answer would be:
-5
-4
-3
-2
-1
0
1
2
3
4
5
