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Katyanochek1 [597]
3 years ago
8

A hose fills a hot tub at a rate of

Mathematics
2 answers:
IrinaVladis [17]3 years ago
5 0
It will take a little over 2 hours to fill the tub
11111nata11111 [884]3 years ago
4 0
It will take 866.09 hours
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alexira [117]
It will be 2 because 19/9 is 2
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Name the minor arc and find its measure.
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3 years ago
3 years from now, Ron's age will be 2 times that of Miley. Three years ago, Ron's age was 3 times that of Miley.
andrezito [222]

Answer:

M=9

EXPLANATION:

Let R represent Ronald’s present age. Let M represent Miley’s present age. Three years from now, Ronald and Miley will be R+3 and M+3 years old, respectively.

Your assertion “Three years from now, Ron’s age will be 2 times that of Miley's” can be written as

R + 3 = 2*(M + 3)

Similarly, your assertion “Three years ago, Ron's age was 3 times that of Miley's” can be written as

R - 3 = 3*(M-3)

We can add the left side of these equations together, and also the right side of these equations together, and obtain a new equation …

R + 3 + R - 3 = 2*(M + 3) + 3*(M - 3) = 2M + 6 + 3M - 9 = 5M - 3

This can be simplified to

2R = 5M - 3

We can divide both sides of the last equation by 2, and obtain ..

(2/2) * R = (5/2) * M - 3/2, or R = (5/2) * M - 3/2.

Now we can “plug in” the last equation into either of our first two equations of this post, and solve for M.

Using the first equation, we have

(5/2) * M - 3/2 + 3 = 2 *(M + 3) = 2M + 6

We now have

(5/2) * M + 3/2 = 2M + 6

The left side of this equation can be rewritten as

(5M + 3) / 2, so we obtain

(5M + 3) / 2 = 2M + 6

Multiplying both sides by 2, we have

5M + 3 = 4M + 12

Subtracting 4M and 3 from both sides, we obtain

M = 9

Miley’s present age is 9.

plss give brainliest

3 0
3 years ago
Somebody please help with this problem
Mrrafil [7]

Step-by-step explanation:

We have been given that AE=BE and \angle1\cong \angle2.

We can see that angle CEA is vertical angle of angle DEB, therefore, m\angle CEA=m\angle DEB as vertical angles are congruent.

We can see in triangles CEA and DEF that two angles and included sides are congruent.

\angle 1\cong \angle 2

AE=BE

\angle CEA\cong\angle DEB or \angle 3\cong \angle 4  

Therefore, \Delta CEA\cong \Delta DEB by ASA postulate.

Since corresponding parts of congruent triangles are congruent, therefore CE must be congruent to DE.

5 0
3 years ago
Someone help me for this algebra task please
Gekata [30.6K]

Answer:

200

Step-by-step explanation:

Substitute 15 for y

\frac{1}{5} x -  \frac{2}{3} (15) = 30

\frac{1}{5} x - 10 = 30

\frac{1}{5} x = 40

x = 200

3 0
3 years ago
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