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Westkost [7]
2 years ago
11

Solve this for most Brainly

Mathematics
1 answer:
Ede4ka [16]2 years ago
5 0

Answer:

1 - 22

2 -

- 4x {y}^{3}  - 6 {x}^{4}  {y}^{3}  + 7 {y}^{4}  - 8 {x}^{4}  {y}^{4}

3- ( x = -4)

4 - Irrational numbers

\sqrt{53}   \:  \:  \:  \:  \:  \sqrt{19}  \:  \:  \:  \: \pi

integers

0 \:  \:  \:  \:  \:  \frac{ - 12}{6}

rational

\frac{2}{3}  \:  \:  \:  \:   \frac{6}{45}

natural numbers 8

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12 midnight ....... tell me
docker41 [41]

Answer:

I am not getting your question .

5 0
3 years ago
Read 2 more answers
Anyone please? Some help would be nice.
marusya05 [52]
Wouldn't the answer be -23/4
7 0
3 years ago
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Find the area of the shaded region. Use 3.14 for at as necessary. PLEASE HELP ASAP!!
ollegr [7]

9514 1404 393

Answer:

  A. 53.5cm^2

Step-by-step explanation:

The area of the circle is ...

  A = πr²

  A = 3.14(5 cm)² = 78.5 cm²

The area of the triangle is ...

  A = 1/2bh

  A = 1/2(10 cm)(5 cm) = 25 cm²

The shaded area is the difference between the circle area and the triangle area:

  shaded = 78.5 cm² -25 cm² = 53.5 cm²

_____

<em>Additional comment</em>

As with many multiple-choice questions, you can simply pick the answer that is not outlandish. The circle will fit into a square that is 10 cm on a side, so its total area is less than 100 cm² (eliminates choice B).

The shaded area is definitely more than 1/4 of that 100 cm² square, so choices C and D are eliminated, too. The only choice that is not unreasonable is choice A.

7 0
2 years ago
I don't really understand what I suppose to do here so please help me with the question​
AlekseyPX

Answer:

look at the time for example, B's time is constant because it isn't skipping numbers like 1, 5, 3,etc.

the height is also constant because it is dividing each number by 2, 60÷2=30, 30÷2=15, 15÷2=7.5. You will notice A is not constant so (no) but B is so (yes)

5 0
2 years ago
Which mixed number shows the result of 671 divided by 83
djverab [1.8K]

Answer:

8 7/83

Step-by-step explanation:

671/83

8.084= 8 7/83

3 0
3 years ago
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