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3 years ago

Write your answer without using negative exponents

Mathematics

1 answer:

Reil [10]3 years ago

5 0

Answer:

$\frac{1}{ {u}^{42} }$

Step-by-step explanation:

From law of indices

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A major fishing company does its fishing in a local lake. The first year of the company's operations it managed to catch 70,000

BaLLatris [955]

Answer:

403200 I think is the answer

Step-by-step explanation:

good luck

8 0

2 years ago

A man needed to sell a car. He priced it at $3,500 the first day. The second day he reduced the price by 15%. What was the price

pashok25 [27]

Answer:

$2,975.00

Step-by-step explanation:

15% off of $3,500 is $2.975

5 0

3 years ago

At a certain time of day, a tree 15 m tall cast a shadow of 12 m, while a second tree cast a shadow of 20 m. How tall is the sec

lilavasa [31]

25 metres tall.

Explanation:

The heights of the trees are directly proportional to the length of their shadows because at the same time of day, the sun will be at the same angle in the sky.

The trees and their shadows form 2 similar triangles:
Write as a proportion:

heightshadow x20=1512

12x=20×15

x=20×1512

x=25 metres tall.

As check: find the constant for each tree:

1512=1.25 and 2520=1.25

i hope this help

8 0

4 years ago

Rope A is longer than rope C but shorter than rope B rope d is shorter than rope c

liberstina [14]

Answer:

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4 0

3 years ago

Let A = { x ∈ R : x 2 − 5 x + 4 ≤ 0 } , B = (3 , 5), and C = (3 , 4]. Show that A ∩ B = C . (Recall, you must show two separate

kolbaska11 [484]

Answer:

You can proceed as follows:

Step-by-step explanation:

First solve the quadratic inequality $x^{2}-5x+4\leq 0$ . To do that, factorize, then we have that $(x-4)(x-1)\leq 0$ . This implies that

$x-1\leq 0\, \text{and}\, x-4\geq 0$

$x-1 \geq 0\, \text{and}\, x-4\leq 0$

In the first case the solution is the empty set $\emptyset$ . In the second case the solution is the interval $1\leq x \leq 4$ . Now we have that

$A=[1,4]$

$B=(3,5)$

$C=(3,4]$ .

To show that $A\cap B\subseteq C$ consider $x\in A\cap B$ . Then $1\leq x \leq 4\, \text{and}\, 1$ , this implies that $3$ , then $x\in C$ . Now, to show that $C\subseteq A\cap B$ consider $x\in C$ , then $3$ , then $1\leq x \leq 4\, \text{and}\, 3$ , then $x\in [1,4] \, \text{and}\, x\in (3,5)$ , this implies that $x\in A\cap B$ .

Observe the image below.

7 0

4 years ago