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Ainat [17]
3 years ago
5

Write your answer without using negative exponents

Mathematics
1 answer:
Reil [10]3 years ago
5 0

Answer:

\frac{1}{ {u}^{42} }

Step-by-step explanation:

From law of indices

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Instructions:Select the correct answer.
Taya2010 [7]
Bro its D i got it right
4 0
3 years ago
Solve the systems by the addition method 2x + y = - 1x - 2y = - 4
inna [77]

Answer:

x = -6/5

y =7/5

Step-by-step explanation:

2x + y = - 1

x - 2y = - 4

Multiply the first equation by 2 so we can eliminate y

2(2x + y = - 1)

4x + 2y = -2

Add this to the second equation

4x + 2y = -2

x - 2y = - 4

---------------------

5x + 0y = -6

Divide by 5

5x/5 = -6/5

x = -6/5

Multiply the second equation by -2 so we can eliminate x

-2(x - 2y = - 4)

-2x+4y = 8

Add this to the first equation

2x + y = - 1

-2x+4y = 8

---------------------

0x + 5y = 7

Divide by 5

5y/5 = 7/5

y =7/5

6 0
3 years ago
What is 2/3x=10 one step equations
stellarik [79]
Multiply both sides by three to get 2x=30
Then divide both sides by 2 to get x=15
7 0
3 years ago
Suppose the exchange rate of Euros to US dollars is $0.89 Euros to $1. How many euros can an individual exchange for $60?
bezimeni [28]
53.4 each dollar is 0.89 so x 60.
7 0
3 years ago
25 POINTS
uysha [10]

Answer:

a reflection over the x-axis and then a 90 degree clockwise rotation about the origin

Step-by-step explanation:

Lets suppose triangle JKL has the vertices on the points as follows:

J: (-1,0)

K: (0,0)

L: (0,1)

This gives us a triangle in the second quadrant with the 90 degrees corner on the origin. It says that this is then transformed by performing a 90 degree clockwise rotation about the origin and then a reflection over the y-axis. If we rotate it 90 degrees clockwise we end up with:

J: (0,1) , K: (0,0), L: (1,0)

Then we reflect it across the y-axis and get:

J: (0,1), K:(0,0), L: (-1,0)


Now we go through each answer and look for the one that ends up in the second quadrant;

If we do a reflection over the y-axis and then a 90 degree clockwise rotation about the origin we end up in the fourth quadrant.

If we do a reflection over the x-axis and then a 90 degree counterclockwise rotation about the origin we also end up in the fourth quadrant.

If we do a reflection over the x-axis and then a reflection over the y-axis we also end up in the fourth quadrant.

The third answer is the only one that yields a transformation which leads back to the original position.

4 0
3 years ago
Read 2 more answers
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