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3 years ago

Write the prime factorization of each number using exponents. 50 = 20 =

Mathematics

1 answer:

OLEGan [10]3 years ago

5 0

50 = 2 x 25 = 2 x 5 x 5 = 2 x 5^2

20 = 2 x 10 = 2 x 2 x 5 = 2^2 x 5

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3,1,2,2,3,2,6,4 ayuda con esto

zalisa [80]

Answer:

Step-by-step explanation:

¿Qué necesitas para encontrar la mediana o el modo medio?

6 0

4 years ago

ASAP ANSWER PLEASE :)

Elan Coil [88]

Answer:

158 in2

Step-by-step explanation:

15+15 = 30

24 + 24= 48

40 + 40 = 80

= 158

4 0

3 years ago

Please help solve with steps: -3 + u = 1/2 ---- 5

Luden [163]

-3/5 + u = 1/2

To find u , you have to shift all the “numbers” to one side

u = 1/2 + 3/5 = 11/10

( note that when -3/5 moves to the other side , the sign changes and become positive “ + “ )

Hope this helps!

7 0

3 years ago

Matt gets paid at home for doing extra chores. Last week, he did 6 loads of laundry and 1

emmasim [6.3K]

Matt earns $4 and $3 for 1 load of laundry and 1 load of dishes respectively

Solution:

Given, Matt gets paid at home for doing extra chores.

We have to find How much does Matt earn for completing each type of chore?

Let the amount for 1 load of laundry be m and amount for 1 load of dish be n.

Now, last week, he did 6 loads of laundry and 1 load of dishes, and his parents paid him $27.

Then, 6 $\times$ amount for 1 load of laundry + 1 $\times$ amount for 1 load of dish = 27

$\rightarrow 6 \mathrm{m}+\mathrm{n}=27 \rightarrow(1)$

The week before, he finished 1 load of laundry and 9 loads of dishes, earning a total of $31

Then, 1 $\times$ amount for 1 load of laundry + 9 $\times$ amount for 1 load of laundry = 31 ⇒m + 9n = 31 ⇒ (2)

Now let us solve equations (1) and (2)

0 – 53n = - 159

-53n = -159

53n = 159

n = 3

Now, substitute n value in (1) ⇒ 6m + 3 = 27 ⇒ 6m = 24 ⇒ m = 4

Hence, matt earns $4 and $3 for 1 load of laundry and 1 load of dishes respectively.

8 0

4 years ago

Evaluate the integral from 0 to 1/2 of xcospixdx

aleksklad [387]

$\bf \int\limits_{0}^{\frac{1}{2}}xcos(\underline{\pi x})\cdot dx\\
-----------------------------\\
u=\underline{\pi x}\implies \frac{du}{dx}=\pi \implies \frac{du}{\pi }=dx\\
-----------------------------\\
thus\implies \int\limits_{0}^{\frac{1}{2}}xcos(u)\cdot \cfrac{du}{\pi }
\\\\
\textit{wait a sec, we need the integrand in u-terms}\\
\textit{what the dickens is up with that "x"?}\qquad well\\
-----------------------------\\
u=\pi x\implies \frac{u}{\pi }=x\\
-----------------------------\\$ $\bf thus
\\\\
\int\limits_{0}^{\frac{1}{2}}\cfrac{u}{\pi }cos(u)\cdot \cfrac{du}{\pi }\implies 
\int\limits_{0}^{\frac{1}{2}}\cfrac{u}{\pi }\cdot \cfrac{cos(u)}{\pi }\cdot du\implies 
\cfrac{u}{\pi^2}\int\limits_{0}^{\frac{1}{2}}cos(u)\cdot du\\
-----------------------------\\
\textit{now, let us do the bounds}
\\\\
u\left( \frac{1}{2} \right)=\pi\left( \frac{1}{2} \right)\to \frac{\pi }{2}
\\\\
u\left( 0 \right)=\pi (0)\to 0\\
-----------------------------\\$ $\bf thus
\\\\
\cfrac{u}{\pi^2}\int\limits_{0}^{\frac{\pi }{2}}cos(u)\cdot du\implies \cfrac{u}{\pi^2}\cdot sin(u)\implies \left[ \cfrac{u\cdot sin(u)}{\pi^2} \right]_{0}^{\frac{\pi }{2}}
$

5 0

3 years ago