Answer:
x + 3y + 9 = 0
Step-by-step explanation:
y=3x + 2
Coefficient of x = 3
Gradient (m) of line y= 3x + 2 is 3
Since the line passing through point
(3,-4) is perpendicular to line y=3x + 2
hence gradient (m) of the line is -1/3;
And hence it equation is given as;
y - y1 = m(x - x1)
y - (-4) = -1/3(x - 3)
multiplying through by 3;
3 × y + 3 × 4 = 3 × -1/3(x - 3)
3y + 12 = -1(x - 3)
3y + 12 = -x + 3
x + 3y + 12 - 3 = 0
x + 3y + 9 = 0
Answer:
y = 5x/2 + 2
Step-by-step explanation:
We know the equation for slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept. Since we have the coordinates of one point on this line and the slope, we can substitute that in and find b first:
y = mx + b
-8 = 5/2(-4) + b
-8 = -10 + b
b = 2
So we can use the slope and this y intercept we found to plug back into the equation:
y = mx + b
y = 5x/2 + 2
Answer: 0.85714285714
Step-by-step explanation:
I just googled it so yeah
Answer:
let the numbers be x and y then by given conditions:
x + y = 10 ….. eq 1
and
xy = 9….. eq 2
from eq 2. y = 9/x
put this in eq. 1
x + 9/x = 10
x + 9= 10x
x = 1
now,
xy = 9put value of x
y = 9
Step-by-step explanation:
Hope it is helpful....
Answer:
25
Step-by-step explanation:
The median of a trapezoid equals one half of the sum of the bases
AC is a median and EB and DF are the bases.
hence AC = 1/2(EB + DF)
We are given that EB = 13 and that AC = 19. And we need to find DF
To do so we plug in what we are given and solve for DF
AC = 1/2(EB + DF)
AC = 19, EB = 13
19 = 1/2(13 + DF)
Now solve for DF
* Multiply both sides by 2*
19 * 2 = 38
1/2(13 + DF) * 2 ( the 1/2 and 2 cancel out and we're left with 13 + DF )
We then have 38 = 13 + DF
* Subtract 13 from both sides *
38 - 13 = 13 - 13 + DF
We get that DF = 25