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3 years ago

What is the slope of the line that passes through the points (9,60 and (14,7)?

1 answer:

4 0

This is (y2-y1)/(x2-x1), y2 being 12, y1 being 7, x2 being -39 and x1 being 26. So if you plug in the points it would be: (12-7)/(-39-26). This solved equals: -5/65 which simplified equals: -1/13

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Add 345 000 to 1.9 million. What is the answer expressed as scientific notation?

Anit [1.1K]

2.245 × 10^6
Since the answer is 2245000, move it over 6 places and use scientific notation.

I hope this helped! If it didn't, or I got it wrong, please reply! If I helped you, please do not forget to mark it the brainliest!

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2 years ago

Find the x and y intercept of the line 4x+2y=24

Elodia [21]

(2,0) (0,4) are the X and Y intercept

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3 years ago

Radio station KLUV broadcast and all directions to a distance of 60 miles. What is the area over which the station can be heard

wlad13 [49]

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3 years ago

Which of the following is equal to g(x)?<br> A. 1/3 (x)<br> B. (x+3)<br> C. (x) - 3<br> D. (x - 3)

DochEvi [55]

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2 years ago

The mean cost of domestic airfares in the United States rose to an all-time high of $385 per ticket (Bureau of Transportation St

saveliy_v [14]

Answer:

a)0.067

b)0.111

c)0.612

d)$687.28

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = $385

Standard Deviation, σ = $110

We are given that the distribution of domestic airfares is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P(domestic airfare is $550 or more)

P(x > 550)

$P( x > 550) = P( z > \displaystyle\frac{550 - 385}{110}) = P(z > 1.5)$

$= 1 - P(z \leq 1.5)$

Calculation the value from standard normal z table, we have,

$P(x > 550) = 1 - 0.933 = 0.067= 6.7\%$

b) P(domestic airfare is $250 or less)

$P(x \leq 250) = P(z \leq \displaystyle\frac{250-385}{110}) = P(z \leq -1.22)$

Calculating the value from the standard normal table we have,

$P( x \leq 250) = 0.111 = 11.1\%$

c))P(domestic airfare is between $300 and $500)

$P(300 \leq x \leq 500) = P(\displaystyle\frac{300 - 385}{110} \leq z \leq \displaystyle\frac{500-385}{110}) = P(-0.77 \leq z \leq 1.04)\\\\= P(z \leq 1.04) - P(z < -0.77)\\= 0.851 - 0.239 = 0.612 = 61.2\%$