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3 years ago

Hey guys! I really need help on this question.. Im stuck on it lol. If you can help then tysm :)

Mathematics

1 answer:

madreJ [45]3 years ago

7 0

Answer:

The average size of a seventh - grade class is larger and varies more than that of kindergarten class.

<h3>PLEASE MARK ME BRAINLIEST</h3>

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Arron spends 1/2 of his $800 weekly wage on rent and 1/4 on repaying the loan for his car. How much money does he have left for

Slav-nsk [51]

Answer:

$200

Step-by-step explanation:

Half of $800 is $400, and a quarter of $800 is $200. $800-$400-$200=$200

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3 years ago

Read 2 more answers

Please Solve this Math Proof

Leokris [45]

There is nothing here....

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4 years ago

I tried the two bottom ones and it’s wrong

Vikentia [17]

Answer:

Step-by-step explanation:

The answer is The cook need 1/12

Why??

3/4 -2/3 = 1 /12

Therefore , the cook need 1/12 heheh Send Love:#

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2 years ago

I NEED HELP PLEASEEEEE I BEG YOU ILL GIVE YOU EXTRA POINTS!!

Romashka [77]

C all triangles are different

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3 years ago

A particle moves along line segments from the origin to the points (2, 0, 0), (2, 4, 1), (0, 4, 1), and back to the origin under

Shkiper50 [21]

The work is equal to the line integral of $\vec F$ over each line segment.

Parameterize the paths

from (0, 0, 0) to (2, 0, 0) by $\vec r_1(t)=t\,\vec\imath$ with $0\le t\le2$ ,
from (2, 0, 0) to (2, 4, 1) by $\vec r_2(t)=2\,\vec\imath+4t\,\vec\jmath+t\,\vec k$ with $0\le t\le1$ ,
from (2, 4, 1) to (0, 4, 1) by $\vec r_3(t)=(2-t)\,\vec\imath+4\,\vec\jmath+\vec k$ with $0\le t\le2$ , and
from (0, 4, 1) to (0, 0, 0) by $\vec r_4(t)=(4-4t)\,\vec\jmath+(1-t)\,\vec k$ with $0\le t\le1$

The work done by $\vec F$ over each segment (call them $C_1,\ldots,C_4$ ) is

$\displaystyle\int_{C_1}\vec F\cdot\mathrm d\vec r_1=\int_0^2\vec0\cdot\vec\imath\,\mathrm dt=0$

$\displaystyle\int_{C_2}\vec F\cdot\mathrm d\vec r_2=\int_0^1(t^2\,\vec\imath+24t\,\vec\jmath+32t^2\,\vec k)\cdot(4\,\vec\jmath+\vec k)\,\mathrm dt=\int_0^1(96t+32t^2)\,\mathrm dt=\frac{176}3$

$\displaystyle\int_{C_3}\vec F\cdot\mathrm d\vec r_3=\int_0^2(\vec\imath+(24-12t)\,\vec\jmath+32\,\vec k)\cdot(-\vec\imath)\,\mathrm dr=-\int_0^2\mathrm dt=-2$

$\displaystyle\int_{C_4}\vec F\cdot\mathrm d\vec r_4=\int_0^1((1-t)^2\,\vec\imath+2(4-4t)^2\,\vec k)\cdot(-4\,\vec\jmath-\vec k)\,\mathrm dt=-2\int_0^1(4-4t)^2\,\mathrm dt=-\frac{32}3$

Then the total work done by $\vec F$ over the particle's path is 46.

8 0

4 years ago