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tankabanditka [31]
3 years ago
10

-2x+y=7y=-4x-11answer choicesa.(3,1)b.(10,-51)c.(0,7)PLEASE SHOW WORK!!

Mathematics
1 answer:
stiv31 [10]3 years ago
8 0
We can use substitution to insert one equation into the other
so then it's -2x+(-4x-11)=7
then it becomes -6x-11=7
then -6x=18
then our answer, x=-3
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Colt1911 [192]
<span><span>1.A triangular section of a lawn will be converted to river rock instead of grass. Maurice insists that the only way to find a missing side length is to use the Law of Cosines. Johanna exclaims that only the Law of Sines will be useful. Describe a scenario where Maurice is correct, a scenario where Johanna is correct, and a scenario where both laws are able to be used. Use complete sentences and example measurements when necessary.
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The Law of Cosines is always preferable when there's a choice.  There will be two triangle angles (between 0 and 180 degrees) that share the same sine (supplementary angles) but the value of the cosine uniquely determines a triangle angle.

To find a missing side, we use the Law of Cosines when we know two sides and their included angle.   We use the Law of Sines when we know another side and all the triangle angles.  (We only need to know two of three to know all three, because they add to 180.  There are only two degrees of freedom, to answer a different question I just did.

<span>2.An archway will be constructed over a walkway. A piece of wood will need to be curved to match a parabola. Explain to Maurice how to find the equation of the parabola given the focal point and the directrix.
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We'll use the standard parabola, oriented in the usual way.  In that case the directrix is a line y=k and the focus is a point (p,q).

The points (x,y) on the parabola are equidistant from the line to the point.  Since the distances are equal so are the squared distances.

The squared distance from (x,y) to the line y=k is </span>(y-k)^2
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The squared distance from (x,y) to (p,q) is </span>(x-p)^2+(y-q)^2.<span>
These are equal in a parabola:

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(y-k)^2 =(x-p)^2+(y-q)^2<span>

</span>y^2-2ky + k^2 =(x-p)^2+y^2-2qy + q^2

y^2-2ky + k^2 =(x-p)^2 + y^2 - 2qy+ q^2

2(q-k)y =(x-p)^2+ q^2-k^2

y = \dfrac{1}{2(q-k)} ( (x-p)^2+ q^2-k^2)

Gotta go; more later if I can.

<span>3.There are two fruit trees located at (3,0) and (−3, 0) in the backyard plan. Maurice wants to use these two fruit trees as the focal points for an elliptical flowerbed. Johanna wants to use these two fruit trees as the focal points for some hyperbolic flowerbeds. Create the location of two vertices on the y-axis. Show your work creating the equations for both the horizontal ellipse and the horizontal hyperbola. Include the graph of both equations and the focal points on the same coordinate plane.

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5 0
3 years ago
Links will be reported
Oxana [17]

Answer:

Center: (-2, 4)

Radius: 4

Step-by-step explanation:

To find the centre and radius, we require to identify g , f and c

By comparing the coefficients of 'like terms' in the given equation with the general form.

2g = 4 → g = 2 , 2f = -8 → f = -4 and c = 4 → center=(−g,−f)=(−2,4)

radius = √22+(−4)2−4= √4+16−4=4

Center: (-2, 4)

Radius: 4

Hope This Helps! :)

8 0
2 years ago
YOOOOOOO HELLLPPPPPP PT.2 <br> HERE 100 PLUS BRAINLIST
pshichka [43]
I believe it is the second one hope that helped
4 0
1 year ago
Read 2 more answers
Please help will give brainliest
deff fn [24]

Since the sum of the probabilities of all possible outcomes must be 100%, we can deduce the following:

  • Cooking in under 20 minutes: 10%
  • Cooking between 20 and 30 minutes: 85%
  • Cooking in more than 30 minutes: 5%

In fact, the probabilities of cooking in less than 20 or more than 30 sum up to 15%, which means that the remaining outcome (i.e. cooking time between 20 and 30) must complete this probability to 15, and in fact 15+85=100.

That being said, all three answers are simply a combination of these three scenarios: let C be the cooking time, for aesthetic reasons:

P(C\geq 20) = P(20 \leq C \leq 30)+P(C\geq30) = 85\%+5\%=90\%

P(20 \leq C \leq 30) = 85\%

P(C\leq 30) = P(C\leq20)+P(20 \leq C \leq 30) = 10\%+85\%=95\%

3 0
2 years ago
A jewelry maker purchased 20 inches of gold chain.She used 3/8 of the chain for a bracelet. How many inches of gold did she have
Mazyrski [523]

Answer:

12.5 inches of gold chain.

Step-by-step explanation:

To get the remaining chain of gold we need to calculate

8/8 - 3/8 = 5/8 of 20 inches

then multiply:

20 * 5/8 =  100/8

100/8 = 12.5 inches

7 0
3 years ago
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