Answer:
The mean and the standard deviation of the sampling distribution of the number of students who preferred to get out early are 0.533 and 0.82
Step-by-step explanation:
According to the given data we have the following:
Total sample of students= 150
80 students preferred to get out 10 minutes early
Therefore, the mean of the sampling distribution of the number of students who preferred to get out early is = 80/150 = 0.533
Therefore, standard deviation of the sampling distribution of the number of students who preferred to get out early= phat - p0/sqrt(p0(1-p)/)
= 0.533-0.5/sqrt(0.5*0.5/15))
= 0.816 = 0.82
5/2 is the answer.
Have a nive day!
Answer:
- a. She needs to hang each triangle from its center of gravity or centroid, which is the point at which the three medians of the triangle intersect.
Step-by-step explanation:
- Medians meet at a centroid of the triangle. The centroid is the triangle's center of gravity.
Hello,
1) order the terms:
3x^3+6x^2+5x+10
2) method: grouping 2 to 2 the terms:
=(3x^3+6x^2)+(5x+10)
=3x^2(x+2)+5(x+2)=(x+2)(3x^2+5)
We know that the measure of arc AC = 92 degrees, and x and y are both inscribed angles of this arc, which means that they will have 1/2 of its measure.
Therefore, x = 1/2 (92) = 46 degrees and y = 1/2 (92) = 46 degrees
x = 46, y = 46 is your answer, or the first option
