Question

Jason is pulling a box across the room. He is pulling with a force of 11 newtons and his arm is making a 37 angle with the horizontal, if the box weighs 10 newtons what is the net force on the box in the vertical direction? Treat up as the positive direction, and down as the negative direction.

Answer 1

Force=10N

Angle=37

Vertical componenets:-

$\\ \sf\longmapsto Fsin\theta$

$\\ \sf\longmapsto 10sin38$

$\\ \sf\longmapsto 10(0.6)$

$\\ \sf\longmapsto 6N$