Consider right triangle ΔABC with legs AC and BC and hypotenuse AB. Draw the altitude CD.
1. Theorem: The length of each leg of a right triangle is the geometric mean of the length of the hypotenuse and the length of the segment of the hypotenuse adjacent to that leg.
According to this theorem,

Let BC=x cm, then AD=BC=x cm and BD=AB-AD=3-x cm. Then

Take positive value x. You get

2. According to the previous theorem,

Then

Answer: 
This solution doesn't need CD=2 cm. Note that if AB=3cm and CD=2cm, then

This means that you cannot find solutions of this equation. Then CD≠2 cm.
Answer:
D. 
Step-by-step explanation:
Let be
. To find the equivalent expression we must use the following property:
(1)
Based on this fact, we find the following equivalence:

Hence, the correct answer is D.
Answer:
Step-by-step explanation:
A) The diagram of the triangle is shown in the attached photo
The lengths of the given triangle form a Pythagoras triple. This means that the square of the longest side equals the sum of the squares of the two shorter sides.
Area = 1/2 × base × height
Height = 3 cm
Base = 4 cm
Area = 1/2 × 3 × 4 = 6 cm²
B) The altitudes can be AB or BC. Therefore, the length of the shortest altitude is AB = 3 cm
The diagonal is the same as the hypotenuse which is also the longest side of the triangle. Thus,
Length of diagonal = 5 cm
Answer:
The correct answer is A. 9.4 inches.
Step-by-step explanation:
Given that the volume of a boys' basketball is 434 cubic inches, and Dan would like to get a ball with half the volume for his son, to determine what is the diameter of the ball that Dan will buy for his son, the following calculation has to be done, knowing that the volume of a sphere is four thirds multiplied by pi multiplied by the radius cubed:
4/3 x 3.14 x X ^ 3 = 434
4.186 x X ^ 3 = 434
X ^ 3 = 434 / 4.186
X = 3√ 103.662
X = 4.7
In turn, since the radius of a sphere is equal to half its diameter, the diameter of the basketball is 9.4 inches (4.7 x 2).