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satela [25.4K]
3 years ago
5

mrs mccarthy runs 6 laps a day on monday wednesdays and fridays. she does yoga on tuesdays and thursdays for 45 minutes. how man

y laps does she runs in 10 weeks? write an equation to solve
Mathematics
1 answer:
LUCKY_DIMON [66]3 years ago
8 0
The answer is 180 because 6 x 3=18 and 18x10=180
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If the degree of a term is a fraction,the term is still a monomial
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False,Monomials only have one term.Example: 6xy<span> . . . . . .A+

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The sides of a right triangle containing the right angle are (5x) cm and (3x - 1) cm. If the area of the triangle be 60 cm, calc
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Answer: hypotenuse (h) = 17 cm

Step-by-step explanation:

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3 years ago
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Explain how to use the missing pieces strategy to compare two fractions. Include a diagram with your explanation.
kozerog [31]
The missing pieces strategy is another method to compare two fractions. To tell which number is larger, you need to see which one is missing less. For example, you have 3/4 versus 4/5. Each of these fractions needs 1 to complete the whole. You need to subtract the numerator with one to compare them. For 3/4 we have 1/4 and for 4/5 we have 1/5. You know that if you complete 4/5 you will get 4. You know that 5 is greater than four. Therefore, 4/5 is larger than 3/4.
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3 years ago
Use the Newton-Raphson method to find the root of the equation f(x) = In(3x) + 5x2, using an initial guess of x = 0.5 and a stop
xxMikexx [17]

Answer with explanation:

The equation which we have to solve by Newton-Raphson Method is,

 f(x)=log (3 x) +5 x²

f'(x)=\frac{1}{3x}+10 x

Initial Guess =0.5

Formula to find Iteration by Newton-Raphson method

  x_{n+1}=x_{n}-\frac{f(x_{n})}{f'(x_{n})}\\\\x_{1}=x_{0}-\frac{f(x_{0})}{f'(x_{0})}\\\\ x_{1}=0.5-\frac{\log(1.5)+1.25}{\frac{1}{1.5}+10 \times 0.5}\\\\x_{1}=0.5- \frac{0.1760+1.25}{0.67+5}\\\\x_{1}=0.5-\frac{1.426}{5.67}\\\\x_{1}=0.5-0.25149\\\\x_{1}=0.248

x_{2}=0.248-\frac{\log(0.744)+0.30752}{\frac{1}{0.744}+10 \times 0.248}\\\\x_{2}=0.248- \frac{-0.128+0.30752}{1.35+2.48}\\\\x_{2}=0.248-\frac{0.17952}{3.83}\\\\x_{2}=0.248-0.0468\\\\x_{2}=0.2012

x_{3}=0.2012-\frac{\log(0.6036)+0.2024072}{\frac{1}{0.6036}+10 \times 0.2012}\\\\x_{3}=0.2012- \frac{-0.2192+0.2025}{1.6567+2.012}\\\\x_{3}=0.2012-\frac{-0.0167}{3.6687}\\\\x_{3}=0.2012+0.0045\\\\x_{3}=0.2057

x_{4}=0.2057-\frac{\log(0.6171)+0.21156}{\frac{1}{0.6171}+10 \times 0.2057}\\\\x_{4}=0.2057- \frac{-0.2096+0.21156}{1.6204+2.057}\\\\x_{4}=0.2057-\frac{0.0019}{3.6774}\\\\x_{4}=0.2057-0.0005\\\\x_{4}=0.2052

So, root of the equation =0.205 (Approx)

Approximate relative error

                =\frac{\text{Actual value}}{\text{Given Value}}\\\\=\frac{0.205}{0.5}\\\\=0.41

 Approximate relative error in terms of Percentage

   =0.41 × 100

   = 41 %

7 0
3 years ago
Given:
Colt1911 [192]
Your question is very confusing but x=8 so just plug in 8 where you see X
3 0
3 years ago
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