(1/5) times (the relay) = 3/4 mile
Multiply each side by 5
The relay = (5) x (3/4) = 15/4 = <span>3.75 miles.</span>
one way is to solve for the invers of the first function
remembe, to solve, replace f(x) or g(x) with y, switch x and y, solve for y and replace it with f⁻¹(x)
A.
f(x)=x/2+8
y=x/2+8
x=y/2+8
x-8=y/2
2x-16=y
f⁻¹(x)=2x-16
nope, not A
B.
f(x)=3x³+16
y=3x³+16
x=3y³+16
x-16=3y³
(x-16)/3=y³
∛((x-16)/3)=y
f⁻¹(x)=∛((x-16)/3)
nope, not the same
not B
C.
f(x)=18/x-9
y=18/x-9
x=18/y-9
x+9=18/y
y(x+9)=18
y=18/(x+9)
f⁻¹(x)=18/(x+9)
correct, the answer is C
answer is C
8 people have finished the race in 30 minutes
Answer:
B; (2,-4)
Step-by-step explanation:
The general equation of a straight line is;
y = mx + b
where m is the slope and b is the y-intercept
So from the question, when we look at the given equation, its slope is -1/2
mathematically, when two lines are perpendicular, the product of their slopes is -1
thus;
m1 * m2 = -1
m2 * -1/2 = -1
-m2 = -2
m2 = 2
The general equation form is;
y-y1 = m(x-x1)
where (x1,y1) = (4,0)
y-0 = 2(x-4)
y = 2x - 8
So, now we look at the point that will work for this equation
For the line that will work, if we substitute its x-value, we get the y-value
Let us take a look at option B
y = 2(2) -8 = 4-8 = -4
we can see that (2,-4) works
\left[x \right] = \left[ 5\right][x]=[5]2(x+1)/−2 = 8−2 _________
_________ Simplifying
\left[x \right] = \left[ 2\right][x]=[2] = x + 1 + -4
x = -5
