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2 years ago

Two hoses from two different taps are used to fill a fishpond. The first hose alone

Mathematics

1 answer:

Paraphin [41]2 years ago

4 0

Answer: 12 minutes

Step-by-step explanation:

Two rates for hoses A and B. FP is the Fish Pond.

A = 20 min/FP or (1/20)FP/min

B = 30 min/FP or (1/30)FP/min

The time in minutes, X, to fill one FP:

1FP = X*((1/20)FP/min) + X*((1/30)FP/min)

1FP = X*(1/20+1/30)FP/min

1FP = X*(2.5/30)FP/min

X = 12 minutes

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Given a leading coefficient of 8, polynomial roots of 1 & 2, and the known point on the graph (4,5). Write an equation that

m_a_m_a [10]

Given:

The leading coefficient of a polynomial is 8.

Polynomial roots are 1 and 2.

The graph passes through the point (4,5).

To find:

The 3rd root and the equation of the polynomial.

Solution:

The factor form of a polynomial is:

$y=a(x-c_1)(x-c_2)...(x-c_n)$

Where, a is a constant and $c_1,c_2,...,c_n$ are the roots of the polynomial.

Polynomial roots are 1 and 2. So, $(x-1)$ and $(x-2)$ are the factors of the polynomial.

Let the third root of the polynomial by c, then $(x-c)$ is a factor of the polynomial.

The leading coefficient of a polynomial is 8. So, a=8 and the equation of the polynomial is:

$y=8(x-1)(x-2)(x-c)$

The graph passes through the point (4,5). Putting $x=4,y=5$ , we get

$5=8(4-1)(4-2)(4-c)$

$5=8(3)(2)(4-c)$

$5=48(4-c)$

Divide both sides by 48.

$\dfrac{5}{48}=4-c$

$c=4-\dfrac{5}{48}$

$c=\dfrac{192-5}{48}$

$c=\dfrac{187}{48}$

Therefore, the 3rd root on the polynomial is $\dfrac{187}{48}$ .

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2 years ago

6. Find the perimeter of the figure below

liraira [26]

Answer:

26 in.

Step-by-step explanation:

» <u>Concepts</u>

The perimeter for a shape is the total distance around it measured in units. The formula to find the perimeter of a trapezoid is a + b + c + d, where a & b are the bases, and c & d are the lengths of the other sides.

» <u>Solution</u>

Adding up all the sides, we get:

$11+7+4+4$
$18+4+4$
$22+4$
$26$

26 inches

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2 years ago

A scientist conducted an experiment. Due to chemical reaction, the temperature of a compound rose 1/10 degree every 1/4 hour for

klio [65]

Answer:

The rate is $\frac{2}{5}$ degree per hour.

Step-by-step explanation:

Given : A scientist conducted an experiment. Due to chemical reaction, the temperature of a compound rose $\frac{1}{10}$ degree every $\frac{1}{4}$ hour for a limited time.

To find : What was the rate, in degrees per hour that the temperature of the compound rose ?

Solution :

In every $\frac{1}{4}$ hour the temperature of a compound rose $\frac{1}{10}$ degree

To get the rate, in degrees per hour,

In every 1 hour the temperature of a compound rose is

$r=\dfrac{\frac{1}{10}}{\frac{1}{4}}$ degree

$r=\dfrac{4}{10}$ degree/hr

$r=\dfrac{2}{5}$ degree/hr

Therefore, the rate is $\frac{2}{5}$ degree per hour.

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2 years ago

How to find x and y (the answer is x=25,y=20 but i couldn't get the answer

Yakvenalex [24]

How are you going to ask a question and answer it yourself w t f

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3 years ago

What is the area of a square when the side length is 2/3cm

Leviafan [203]

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3 years ago