Answer:
see explaination
Step-by-step explanation:
Using the formulla that
sum of terms number of terms sample mean -
Gives the sample mean as \mu=17.954
Now varaince is given by
s^2=\frac{1}{50-1}\sum_{i=1}^{49}(x_i-19.954)^2=9.97
and the standard deviation is s=\sqrt{9.97}=3.16
b) The standard error is given by
\frac{s}{\sqrt{n-1}}=\frac{3.16}{\sqrt{49}}=0.45
c) For the given data we have the least number in the sample is 12.0 and the greatest number in the sample is 24.1
Q_1=15.83, \mathrm{Median}=17.55 and Q_3=19.88
d) Since the interquartile range is Q_3-Q_1=19.88-15.83=4.05
Now the outlier is a number which is greater than 19.88+1.5(4.05)=25.96
or a number which is less than 15.83-1.5(4.05)=9.76
As there is no such number so the given sample has no outliers
9.35 times 10 to the second power
Approximately 1700 megawatts of electricity could be supplied by Hydropower in 2017. Option B is correct.
Given that,
In 2017 there were enough renewable energy sources to supply a total of 9309 megawatts of electricity in a country. The graph shows the proportions that the different renewable energy sources could supply.
<h3>What are percentages?</h3>
the percentage is the ratio of the composition of matter to the overall composition of matter multiplied by 100.
Here, from the graph contribution of the hydropower is 18.2%.
So the electricity produced through hydropower is,
= 9309 * 18.2%
= 9309 * 18.2/100
= 1694.23
≈ 1700 megawatts
Thus, approximately 1700 megawatts of electricity could be supplied by Hydropower in 2017.
Learn more about percentages here:
brainly.com/question/13450942
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Answer:
Yes
Step-by-step explanation:
Answer is option B.
Explanation:
5 to the power -2 can be written as
which will be
which will be
