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ludmilkaskok [199]
1 year ago
9

Prove that cos^4∆ - sin^4∆ = 2cos^2∆ - 1

Mathematics
1 answer:
GarryVolchara [31]1 year ago
3 0

\cos^{4} x-\sin^{4} x\\\\=(\cos^{2} x+\sin^{2} x)(\cos^{2} x-\sin^{2} x)\\\\=\cos^{2} x-\sin^{2} x\\\\=\cos^{2} x-(1-\cos^{2} x)\\\\=2\cos^{2} x-1

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Can someone help me plz and thank u
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Answer:

<A = 44

Step-by-step explanation:

A triangle is 180 degrees

(x+59) + (x+51) + 84 = 180        >> add everything on the left side

2x + 194 = 180                          >> subtract both sides by 194

2x = -14                                     >> divide both sides by 2 to get x alone

x = -7

since you are finding A<, substitute

<A = x + 51

<A = (-7) + 51

<A = 44  

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