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ludmilkaskok [199]
1 year ago
9

Prove that cos^4∆ - sin^4∆ = 2cos^2∆ - 1

Mathematics
1 answer:
GarryVolchara [31]1 year ago
3 0

\cos^{4} x-\sin^{4} x\\\\=(\cos^{2} x+\sin^{2} x)(\cos^{2} x-\sin^{2} x)\\\\=\cos^{2} x-\sin^{2} x\\\\=\cos^{2} x-(1-\cos^{2} x)\\\\=2\cos^{2} x-1

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What is the slope of the line that passes through the points (-9, -8)((−15,−16)? Write your answer in simplest form.
alexandr402 [8]

Answer:

Therefore the slope of the line that passes through the points (-9, -8),(−15,−16) is

Slope=\dfrac{4}{3}

Step-by-step explanation:

Given:

Let,

point A( x₁ , y₁) ≡ ( -9 ,-8)

point B( x₂ , y₂ )≡ (-15 ,-16)

To Find:  

Slope = ?

Solution:

Slope of Line Segment AB is given as

Slope(AB)=\dfrac{y_{2}-y_{1} }{x_{2}-x_{1} }

Substituting the values we get

Slope(AB)=\dfrac{-16-(-8)}{-15-(-9)}\\\\Slope(AB)=\dfrac{-16+8}{-15+9}\\\\Slope(AB)=\dfrac{-8}{-6}=\dfrac{4}{3}

Therefore the slope of the line that passes through the points (-9, -8),(−15,−16) is

Slope(AB)=\dfrac{4}{3}

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3 years ago
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3 years ago
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Answer:

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2 years ago
What are the domain restrictions of a + 1 / a^2-5a-36?
velikii [3]
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The domain of an expression is the range of all values for which the expression is defined. Looking at the expression, it will legal everywhere except when a^2 - 5a - 36 is equal to 0. Since that's a quadratic equation, we can use the quadratic formula to find where its value is 0, giving -4 and 9.    

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3 years ago
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Alex17521 [72]
Option A. would be the best answer.
Hope this helps ;)
7 0
2 years ago
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