Answer:
1496.52 Pa, 14.76 atm
Step-by-step explanation:
This question can be solved using ideal gas law
according to which
pv = nrt
where p is the pressure of gas
v is volume of gas
n is amount gas in moles
R is ideal gas constant whose value is 8.314 J/mol
T is absolute temperature of gas on Kelvin scale
______________________________
given
v = 5 liter
n = 3
T = 300 kelvin
R = 8.314 J/mol
Let the pressure be p
Substituting the above value in ideal gas law equation we have
p*5 = 3*8.314*300
p = 7482.6/5 = 1496.52 Pa
This pressure is in pascal while option is in atm
we know 1 Pascal is equal to 0.0000098692 atm
we know that 1 Atm = 101325 Pa
thus, 1496.52 is equal to 0.0000098692*1496.52 atm
1496.52 is equal to 14.76 atm
Answer:
Step-by-step huh vunefvjefeffj. Vf Jeff vfnu
1/2 = 5/10
Each friend gets 1/10
If it also count Camille:
1/2 = 6/12
Each friend gets 1/12
Answer:
The distance from AD to BC is 7
Step-by-step explanation:
The information given are;
The type of inscribed quadrilateral ABCD = Isosceles trapezoid
The radius of the circle = 5
Segment AD of ABCD = 6
The median of the trapezoid ABCD = 7
Given the trapezoid theorem, the median is equal to half the length of the two bases added together, we have;
(AD + BC)/2 = 7
Which gives;
(6 + BC)/2 = 7
BC = 7×2 - 6 = 8
Therefore the distance from AD to BC is given by the distance from BC to the median line added to the distance from AD to the median line given as follows;
The distance from BC to the median = √(Radius² - (BC/2)²) = √(5² - (8/2)²) = 3
The distance from BC to the median = 3
The distance from AD to the median = √(Radius² - (AD/2)²) = √(5² - (6/2)²) = 4
Which gives;
The distance from AD to BC = 3 + 4 = 7
